Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
DD =25
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the solution answered is available and even the answers for 25th in table i just need explanation
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M person | 80 | kg | safe |
m ladder | 30 | kg | caution |
unsafe | |||
L/3 mass fraction | |||
0.37878788 | |||
L mass fraction | |||
0.86363636 | |||
Nfloor | 1078 | N | |
Nwall max | 270 | N | available |
Ff max | 270 | N | available |
L/3 way up the ladder | top of ladder | |||||||||||
DOB | Theta deg | radians | Tan theta | Cot theta | mu required | Ff required | mu required | Ff reqd | ||||
25 | 80 | 1.3962634 | 6 | 0.17632698 | 0.0668 | 72.0 | 0.1523 | 164.2 |



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