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A bent tube is attached to a wall with brackets as shown. .A force of F= 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: "parallel * perpendicular = Ftotal

A bent tube is attached to a wall with brackets as shown. .A force of F= 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector I DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: "parallel * perpendicular = Ftotal

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A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector T DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: parallel * perpendicular = Ftotal 2013 Michael Swanbom d values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F- k) lb a. b. F|DA k) lb and FL DA = j+ k) lb of
Transcribed Image Text:A bent tube is attached to a wall with brackets as shown. . A force of F = 970 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the force vector F in Cartesian components. b.) Resolve the force vector F into vector components parallel and perpendicular to the position vector T DA- Express each of these vectors in Cartesian components. NOTE: The parallel component of the force is the same as the force along that direction. The perpendicular component of the force can be found from the relationship: parallel * perpendicular = Ftotal 2013 Michael Swanbom d values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. d 78 in h 57 in g 60 in Variable value 13 in 36 in 45 in F- k) lb a. b. F|DA k) lb and FL DA = j+ k) lb of
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