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C₍ₗ₎ = 15 kJ/mol D₍ₛ₎ = -30 kJ/mol Experiment shows that the heat of reaction of reaction 1 is twice the amount of the heat of reaction of reaction 2 (say, heat of reaction of reaction 1 is 10, therefore, heat of reaction of reaction 2 is 5). Determine the heat of formation (at standard state) of A₍ₛ₎ in kJ/mol

C₍ₗ₎ = 15 kJ/mol D₍ₛ₎ = -30 kJ/mol Experiment shows that the heat of reaction of reaction 1 is twice the amount of the heat of reaction of reaction 2 (say, heat of reaction of reaction 1 is 10, therefore, heat of reaction of reaction 2 is 5). Determine the heat of formation (at standard state) of A₍ₛ₎ in kJ/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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When A reacts with B, the reaction produces C and D (reaction 1):

A₍ₛ₎ + 2B₍ₗ₎ → 3C₍ₗ₎ + D₍ₛ₎

But when A reacts with C, the reaction produces B and D (reaction 2):

3A₍ₛ₎ + 2C₍ₗ₎ → B₍ₗ₎ + 2D₍ₛ₎

The heat of formation (at standard state) for A₍ₛ₎ is not available in any literature; however, the heat of formation (at standard state) for B, C, and D are available:

B₍ₗ₎ = 25 kJ/mol
C₍ₗ₎ = 15 kJ/mol
D₍ₛ₎ = -30 kJ/mol

Experiment shows that the heat of reaction of reaction 1 is twice the amount of the heat of reaction of reaction 2 (say, heat of reaction of reaction 1 is 10, therefore, heat of reaction of reaction 2 is 5).

Determine the heat of formation (at standard state) of A₍ₛ₎ in kJ/mol.

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