By = (v1, v2, v3, v4) is a basis for the space V and Bw = (w1, w2, w3) is a basis for the space W. the linear 1 2 2 5 transformation T:V→W has matrix 1 3 3 7 with 1 1 1 3 respect to (By, Bw). If -2v1 – v2 + av3 + bv4 E Ker(T), then what is the value of a? O -2 -3 O 1 O -1 O 2

By = (v1, v2, v3, v4) is a basis for the space V and Bw = (w1, w2, w3) is a basis for the space W. the linear 1 2 2 5 transformation T:V→W has matrix 1 3 3 7 with 1 1 1 3 respect to (By, Bw). If -2v1 – v2 + av3 + bv4 E Ker(T), then what is the value of a? O -2 -3 O 1 O -1 O 2

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Linear Algebra

In mathematics, problems can be solved by the arithmetic operators like addition, subtraction, multiplication, and division. In algebra, we represent the numbers by any letter called a variable. If these variables are of degree 1, then it is studied under linear algebra. The first-degree equations involving algebraic expressions are called linear equations. That is, if you represent it by drawing a graph you will get a straight line.

Question

By
= (v1, v2, v3, v4) is a basis for the space V and
Bw = (w1, w2, w3) is a basis for the space W. the linear
1
2 2 5
transformation T:V→W has matrix
1 3
3
7
with
1 1
1
3
respect to (By, Bw).
If
-2v1 – v2 + av3 + bv4 E Ker(T), then what is the value of a?
O -2
-3
O 1
O -1
O 2

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