By (v1, v2 , V3 , V4) is a basis for the space V and Bw = (w1, w2, w3) is a basis for the space W. The linear 1 1 3 4 transformation T :V → W has matrix 1 2 2 3 with 1 4 0 1 respect to (By, Bw). If -4 -5 1 , [u2]By 1 1 , [u3]B, which 1 1 of (u1, u2, u3) is in Ker(T)? Only u1 O Only u1 and uz O Every one of the vectors is in Ker(T). O Only U1 and U2 O Only U2
By (v1, v2 , V3 , V4) is a basis for the space V and Bw = (w1, w2, w3) is a basis for the space W. The linear 1 1 3 4 transformation T :V → W has matrix 1 2 2 3 with 1 4 0 1 respect to (By, Bw). If -4 -5 1 , [u2]By 1 1 , [u3]B, which 1 1 of (u1, u2, u3) is in Ker(T)? Only u1 O Only u1 and uz O Every one of the vectors is in Ker(T). O Only U1 and U2 O Only U2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![By
(v1, v2 , V3 , V4) is a basis for the space V and
Bw = (w1, w2, w3) is a basis for the space W. The linear
1
1 3 4
transformation T :V → W has matrix
1
2 2 3
with
1
4 0
1
respect to (By, Bw). If
-4
-5
1
, [u2]By
1
1
, [u3]B,
which
1
1
of (u1, u2, u3) is in Ker(T)?
Only u1
O Only u1 and uz
O Every one of the vectors is in Ker(T).
O Only U1 and U2
O Only U2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92207898-9d84-4f6b-a174-6bfab14e9a46%2F902bb815-9c6d-473e-9ad8-9540ee57c337%2Fnddi0u_processed.png&w=3840&q=75)
Transcribed Image Text:By
(v1, v2 , V3 , V4) is a basis for the space V and
Bw = (w1, w2, w3) is a basis for the space W. The linear
1
1 3 4
transformation T :V → W has matrix
1
2 2 3
with
1
4 0
1
respect to (By, Bw). If
-4
-5
1
, [u2]By
1
1
, [u3]B,
which
1
1
of (u1, u2, u3) is in Ker(T)?
Only u1
O Only u1 and uz
O Every one of the vectors is in Ker(T).
O Only U1 and U2
O Only U2
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