By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = /( TT 4)
By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = /( TT 4)
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Question
![By substitution, we get the following
dq = 4BT
dr
Using Integration operation and evaluating its limits, the equation, leads to
Q =
Rearranging, we get
B =
4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4dc607df-687a-4fcc-ae41-8e9f4a1de482%2Fd9762604-54ff-4b1c-88a2-e59b6023595a%2Fd5pwlxf_processed.png&w=3840&q=75)
Transcribed Image Text:By substitution, we get the following
dq = 4BT
dr
Using Integration operation and evaluating its limits, the equation, leads to
Q =
Rearranging, we get
B =
4)
![A non-uniformly charged insulating sphere has a volume charge density p that is expressed as
p= Br
where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere
is Q and its maximum radius is R. What is the value for B?
Sol.
By definition, the volume charge density is expressed infinitesimally as
p=
where in
is the infinitesimal charge and
is the infinitesimal volume.
so, we have
p = dq/
So we can write this as
dq = B
dV
%3D
But,
dV =
dr](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4dc607df-687a-4fcc-ae41-8e9f4a1de482%2Fd9762604-54ff-4b1c-88a2-e59b6023595a%2Femrbr7k_processed.png&w=3840&q=75)
Transcribed Image Text:A non-uniformly charged insulating sphere has a volume charge density p that is expressed as
p= Br
where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere
is Q and its maximum radius is R. What is the value for B?
Sol.
By definition, the volume charge density is expressed infinitesimally as
p=
where in
is the infinitesimal charge and
is the infinitesimal volume.
so, we have
p = dq/
So we can write this as
dq = B
dV
%3D
But,
dV =
dr
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