Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
By reference to the reacting ratio of NaOH and Ch3COOH, deduce the number of moles of CH3COOH required to reach equivalence.
Transcribed Image Text:Analysis
Calculate the number of moles of NaOH required to reach equivalence.
Concentration Of Acetic Acid= The volume of NaOH x The concentration of NaOH/ The concentration of
Vinegar
42.366 cm x 0.10mol dm/5.00cm
To find the molarity of Acetic acid (Assuming Vinegar has 100% acetic acid)
No.of moles of Acetic acid = Molarity x Volume in L
= 0.85 mol/L x 5.00 x 103 L
= 4.3 x 103 mol
CH,СООН + NaОН %3D СH,СОONa + H.O
1 mole of Acetic acid reacts with 1 mole of NaOH.
the no. of moles of NaOH = the no, of moles of Acetic acid
The reacting ratio of NaOH: Acetic acid = 1: 1
So, the no. of moles of NaOH is also 4.3 x 103 mol
%3D
• By reference to the reacting ratio of NaOH and CH,COOH, deduce the number of moles of CH,COOH required
to reach equivalence.
田
Transcribed Image Text:2.
Titration of sodium hydroxide and vinegar
Method
Fill a burette with the solution of NaOH(aq) standardized in part 1.
2
Pipette 5.00 cm' of vinegar onto a clean conical flask.
3
Add a few drops of the indicator phenolphthalein solution to the conical flask and stand it on a white tile or
white paper.
4
Titrate the NaOH against the vinegar, until the endpoint of the indicator is observed, and record the volume
added from the burette.
Repeat the titration until values within 0.05 cm³ are obtained.
Results
Volume NaOH
Titration 1
Titration 2
Titration 3
end volume / cm³ +0.05
42.4
42.5
42.2
start volume / cm + 0.05
titre / cm' + 0.10
42.4
42.5
42.2
average titre / cm³ ± 0.10 = 42.366
%3D
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