Lightning can be studied with a Van de Graaff generator, which consists of a spherical dome on which charge is continuously deposited by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in the figure below. Assume the dome has a diameter of 26.0 cm and is surrounded by dry air with a "breakdown" electric field of 3.00 106 V/m. (a) What is the maximum potential of the dome? Your response differs from the correct answer by more than 10%. Double check your calculations. kV(b) What is the maximum charge on the dome? ### Understanding Lightning with a Van de Graaff GeneratorLightning can be studied using a Van de Graaff generator, which features a spherical dome where charge is continuously deposited via a moving belt. This process continues until the electric field at the dome's surface reaches the dielectric strength of air. Beyond this point, excess charge results in sparks as visualized in the image provided. Assume the dome has a diameter of **26.0 cm** and is in an environment with dry air, having a "breakdown" electric field of **3.00 × 10⁶ V/m**.![Electric Field Sparks](https://www.shutterstock.com)#### (a) Calculating Maximum Potential of the Dome:- **Question**: What is the maximum potential of the dome?- **Feedback**: Your response differs from the correct answer by more than 10%. Please double-check your calculations. (Units: kV)#### (b) Determining Maximum Charge on the Dome:- **Question**: What is the maximum charge on the dome?- **Feedback**: Your response significantly differs from the correct answer. Rework your solution from the beginning and verify each step carefully. (Units: µC)

Solution: a). The maximum potential can be written in terms of an electric field as given below,…

by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in the figure below. Assume the dome has a diameter of 26.0 cm and is surrounded by dry air with a "breakdown" electric field of 3.00 106 V/m. (a) What is the maximum potential of the dome? Your response differs from the correct answer by more than 10%. Double check your calculations. kV (b) What is the maximum charge on the dome

by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in the figure below. Assume the dome has a diameter of 26.0 cm and is surrounded by dry air with a "breakdown" electric field of 3.00 106 V/m. (a) What is the maximum potential of the dome? Your response differs from the correct answer by more than 10%. Double check your calculations. kV (b) What is the maximum charge on the dome

Similar questions

Two horizontal parallel plates are separated by a distance of 174 mm creating an electric field of 23 μN/C directed north. An electron is place halfway between the two plates with and fired with initial velocity 58 m/s from the horizontal. Calculate the time it takes for the electron to land at the positive plate and its speed before hitting the plate. Provide an Illustration and answer in GRESA format.
A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. O (a) Calculate the acceleration of the electron if the field strength is 7.96 x 10¹ N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. The other side of the positive plate also has a negative charge. There is no field outside the plates.
A uniform electric field 3.41E3 N/C is applied in a cubic box with each side being 2.23 m long. What is the energy stored by the electric field in the box (in J)?
An electron has an initial speed of 5.21 x 106 m/s in a uniform 4.69 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/s
A parallel plate capacitor with a charge of +/-177nC has square plates length L=20.0cm across on each side. The plates are separated by a distance d=10.0cm. A positive +4.0microC point charge is held in place halfway between each plate on the right-most edge of the capacitor. While solving this problem ignore any distortion of the capacitor's electric field along its edges. A) What is the magnitude and direction of the capacitor's electric field at point P, which is midway between the plates and on the left-most edge of the capacitor B) What is the magnitude and direction of the electric field due to the +4.0 microC point charge at point P. C) What is the magnitude and direction of the net electric field at point P
An alpha particle (a helium nucleus) is traveling along the positive x-axis at 1075 m/s when it enters a cylindrical tube of radius 0.800 cm centered on the x-axis. Inside the tube is a uniform electric field of 3.00 10-4 N/C pointing in the negative y-direction. How far does the particle travel before hitting the tube wall? Neglect any gravitational forces. Note: m? = 6.64 10-27 kg; q? = 2e. m
A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.
parallel-plate capacitors are widely used in electronics such as preventing direct current leakage. An electric field is generated between a pair of plates that has a surface charge density of 7.70 x 10^-6 C/m^2 The plates are seperated by 0.49 um. a) what is the magnitude of the electric field between the plates ? b) suppose the thickness of the plates doubled, would my answer increase, decrease, or remain the same?
Problem 12: A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. E = 2.4 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.4 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.
An electron is projected into a uniform electric field that has a magnitude of 500 N/C. The direction of the electric field is vertically upward. The initial velocity of the electron has a magnitude of 6.00x10^6 m/s, and its direction is at an angle of 30°above the horizontal. Find:I. The maximum distance the electron rises vertically above its initial elevation.II. After what horizontal distance does the electron return to its original elevation.
I need help for these questions, I am studying for the physics exam and I couldn't solve this questions which are in the study plan of physics-102. Thanks in advance.