Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw all the major products resulting from the reactions below, taking into consideration both the regioselectivity and stereoselectivity of the reactions. If pairs of enantiomers form, draw both enantiomers. (NOTE: for the second reaction, draw out the hydrogen.)
![The image depicts two separate chemical reactions involving a benzene derivative with a propenyl side chain.
### Reaction 1:
- **Starting Material:** A benzene ring with a propenyl group attached.
- **Reagents:**
- **Br₂ (Bromine):** Used for halogenation.
- **CH₃CH₂OH (Ethanol) in large excess:** Acting as a solvent.
- **Reaction Description:** This is likely a halogenation reaction where the allylic position (the carbon adjacent to the double bond) is brominated in the presence of bromine and ethanol. The large excess of ethanol implies it serves primarily as a solvent rather than a reactant involved in chemical change.
### Reaction 2:
- **Starting Material:** Same as in Reaction 1.
- **Reagent:**
- **H₂ (Hydrogen gas):** Used for hydrogenation.
- **Pd/C (Palladium on carbon):** A catalyst used to facilitate the hydrogenation.
- **Reaction Description:** This reaction involves the hydrogenation of the double bond in the propenyl side chain. The use of H₂ in the presence of Pd/C catalyst typically reduces the double bond to a single bond, resulting in a saturated hydrocarbon chain.
These reactions are common in organic synthesis for modifying the properties of aromatic compounds by changing side chains, useful in various chemical industries, including pharmaceuticals and materials science.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F277d8e9e-796c-4923-a9a2-4c05d5ad95df%2Fb45b3c72-e192-4d81-bea2-5464cb408937%2Flsqr5r_processed.png&w=3840&q=75)
Transcribed Image Text:The image depicts two separate chemical reactions involving a benzene derivative with a propenyl side chain.
### Reaction 1:
- **Starting Material:** A benzene ring with a propenyl group attached.
- **Reagents:**
- **Br₂ (Bromine):** Used for halogenation.
- **CH₃CH₂OH (Ethanol) in large excess:** Acting as a solvent.
- **Reaction Description:** This is likely a halogenation reaction where the allylic position (the carbon adjacent to the double bond) is brominated in the presence of bromine and ethanol. The large excess of ethanol implies it serves primarily as a solvent rather than a reactant involved in chemical change.
### Reaction 2:
- **Starting Material:** Same as in Reaction 1.
- **Reagent:**
- **H₂ (Hydrogen gas):** Used for hydrogenation.
- **Pd/C (Palladium on carbon):** A catalyst used to facilitate the hydrogenation.
- **Reaction Description:** This reaction involves the hydrogenation of the double bond in the propenyl side chain. The use of H₂ in the presence of Pd/C catalyst typically reduces the double bond to a single bond, resulting in a saturated hydrocarbon chain.
These reactions are common in organic synthesis for modifying the properties of aromatic compounds by changing side chains, useful in various chemical industries, including pharmaceuticals and materials science.
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