Br Br: H20 oxonium ion bromide alkyl bromide

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a) What is the approximate pka of the Oxonium ion drawn above. b)draw a reaction coordinate diagram for the reaction c) the bromide ion is acting as a…?
### Chemical Reaction Mechanism

This diagram illustrates a chemical reaction involving the conversion of an oxonium ion to an alkyl bromide.

1. **Oxonium Ion**: 
   - On the left, a cyclic alkane is attached to an oxonium ion (illustrated as a three-membered oxygen atom with a positive charge, bonded to two hydrogen atoms).

2. **Reagent - Bromide Ion (\( \text{Br}^- \))**:
   - The bromide ion is depicted as a reactant, with a lone pair of electrons acting as a nucleophile. This ion is shown with a negative charge indicating its potential to donate electrons.

3. **Reaction Arrow**:
   - The arrow indicates the direction of the reaction, showing the transformation from reactants to products.

4. **Products**:
   - **Alkyl Bromide**: The central product is an alkyl bromide where the bromide ion has replaced the oxonium ion, resulting in a bromine atom bonded to the alkane.
   - **Water (\( \text{H}_2\text{O} \))**: Water is produced as a byproduct of this reaction.

This reaction is typically a type of substitution, where the oxonium ion is replaced by the bromide ion, resulting in the formation of an alkyl bromide and water.
Transcribed Image Text:### Chemical Reaction Mechanism This diagram illustrates a chemical reaction involving the conversion of an oxonium ion to an alkyl bromide. 1. **Oxonium Ion**: - On the left, a cyclic alkane is attached to an oxonium ion (illustrated as a three-membered oxygen atom with a positive charge, bonded to two hydrogen atoms). 2. **Reagent - Bromide Ion (\( \text{Br}^- \))**: - The bromide ion is depicted as a reactant, with a lone pair of electrons acting as a nucleophile. This ion is shown with a negative charge indicating its potential to donate electrons. 3. **Reaction Arrow**: - The arrow indicates the direction of the reaction, showing the transformation from reactants to products. 4. **Products**: - **Alkyl Bromide**: The central product is an alkyl bromide where the bromide ion has replaced the oxonium ion, resulting in a bromine atom bonded to the alkane. - **Water (\( \text{H}_2\text{O} \))**: Water is produced as a byproduct of this reaction. This reaction is typically a type of substitution, where the oxonium ion is replaced by the bromide ion, resulting in the formation of an alkyl bromide and water.
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