Answered: box weighing 100 N is at rest on a… | bartleby

Related questions

Question

A box weighing 100 N is at rest on a horizontal floor. The coefficient of static friction between the box
and the floor is 0.4. What is the smallest force F exerted eastward and upward at an angle of 30o with
the horizontal that can start the box in motion?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

An object of mass 50kg is pushed in the +x direction with a force of 40N flat along a horizontal surface causing a net acceleration of 0.15m/s2 in the +x direction. What is the coefficient of kinetic friction between the surface and the object?
A horse is harnessed to a sled having a mass of 236 kg, includingsupplies. The horse must exert a force exceeding 1 240N at an angle of 35.0° in order to get the sled moving. Treatthe sled as a point particle. (a) Calculate the normal force onthe sled when the magnitude of the applied force is 1 240 N.(b) Find the coefficient of static friction between the sled andthe ground beneath it. (c) Find the static friction force whenthe horse is exerting a force of 6.20 x 102 N on the sled at thesame angle.
A moving truck (m = 3200 kg) is parked on a hill that is inclined at an angle of 11◦ from the horizontal. Assuming that the static friction between the truck and surface on which it is parked is at its maximum value, what is the coefficient of static friction of the surface?
During strenuous exercise, it is possible to exert forces to the joints that are easily ten times greater than the weight being supported. What is the maximum force of friction (in N) under such conditions? (The frictional forces in joints are relatively small in all circumstances except when the joints deteriorate, such as from injury or arthritis. Increased frictional forces can cause further damage and pain.) she exert 67.0 kg of her mass on that knee?
Two boxes (Box A = 9.7 kg and Box B = 5.4 kg) are connected by acord running over a pulley. The coefficient of kinetic friction betweenbox A and the table is 0.18. We ignore the mass of the cord and pulleyand any friction in the pulley, which means we can assume that a forceapplied to one end of the cord will have the same magnitude at theother end. We wish to find the tension of the cord while accelerating (inN), assuming the cord doesn’t stretch. As box B moves down, box Amoves to the right. Hint: Solve for the acceleration of the system first.
Our 10.0-kg mystery box rests on a horizontal floor. The coefficient of static friction is 0.40 and the coefficient of kinetic friction is 0.30. Determine the force of friction, acting on the box if a horizontal applied force is exerted on it of magnitude: (a) 0, (b) 10 N, (c) 20 N Use 9.81m/s sqaured for the gravity and also F sub A unit for the applied force
A 9.61kg box on a ramp with an incline of 26.36° slips, giving it an acceleration of 0.31m/s2. What is the coefficient of kinetic friction between the box and the ramp?