Both deuterons and alpha particles can cause direct reactions by stripping. Which are more effective? Explain.
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Both deuterons and alpha particles can cause direct reactions by stripping. Which are more effective? Explain.
Given:
To explain the deuterons and alpha particles using stripping is given as,
Step by step
Solved in 2 steps
- Once again, the final products have less mass than the 2 nuclei that fuse together; find the missing mass that converts to energy in the last reaction. Using the numbers in the Atomic Mass column, calculate 3He + 3He H-H- 4He. Type the entire calculator answer carefully. [it should be positive, similar in style to 0.012179] (1) Atomic (2) Element (3) Symbol (4) Mass (5) % Abundance (or Radioactive Decay Mode) (7) Half-life (if radioactive) Atomic Number Number, Mass 0. (Neutron) 1.008665 10.4 min Hydrogen Deuterium Tritium H. 99.985% 0.015% 1.007825 2.014102 T. 1 3 3.016049 12.33 yr Helium Не 0.000137% 99.999863% 3 3.016029 4. 4.002602 3. Lithium Li 6.015121 7.016003 7.5% 92.5% 4 Beryllium EC, 7 100% Be 7.016928 53.29 days 9.012182 67 9Question 1: The table shows two isotopes of potassium and two isotopes of calcium. 39K 39 Ca Stable ß* decay 38.96371 38.9707 Type of emission Mass of neutral atom / u Number of electrons Number of protons Number of neutrons Total mass/u Mass defect / u Binding energy / J 42K ß decay 41.9624 Mass of the neutron = 1.008665 u 19 19 ta min 23 42.34797 0.38557 5.76 x 10-11 2 051 oqque 42 Ca stable 41.95863 Mass of the electron = 0.000549 u Mass of the proton = 1.007276 url millons voled pringle bre noljenimaxe al prderobny v nollenimexe erit lo anpitibnco art di ballamos svar en talean blow tert elshatem vos maxe erii otni triquonion aver a) Use data about potassium-42 to explain the concept of mass defect. oo will teanu snimaxe edt sot jaqeq maxe eft overmat ym of 820308 ever b) Complete the table and to calculate the mass defect and binding energy of 39K. Show your calculations in the space below.What becomes of the loss in mass when heavy nuclei split? b) What formula can be used to account for this loss?
- View imageb) What type of decay is happening in the equation below? State two of the conservation laws that apply and explain how they are satisfied 238 92 U 234 Th + 4 a 90 2 c) Use the graph below to calculate the half-life of Protactinium 234, explain how you got your answer. Half Life of Protactinium 234 50 40 30 20 10 222222° 80 70 60 Activity (Bq) 0 20 20 40 40 60 80 100 120 140 160 Time (seconds)Uranium-235 decays spontaneously by nucleon emission. a) Write a balanced equation to show the decay of Uranium-235, 2U, that leads to the formation of Uranium- 235 234 and name all the particles involved b) Write a balanced equation to show the decay of Uranium-235, U, that leads to the formation of 92 Thorium-231. Name all the particles involved.