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Boron (B; Z=5) has two naturally occurring isotopes. Find the percent abundances of 1°B and 11B given these data: atomic mass of B=10.81 amu, isotopic mass of 1°B=10.0129 amu, and isotopic mass of 1"B=11.0093 amu. Round your answer to the nearest hundredth. (Hint: The sum of the fractional abundances is 1. If x=abundance of 1ºB, then 1-x= abundance of 11 B) % abundance of 10B = % % abundance of 11B =

Boron (B; Z=5) has two naturally occurring isotopes. Find the percent abundances of 1°B and 11B given these data: atomic mass of B=10.81 amu, isotopic mass of 1°B=10.0129 amu, and isotopic mass of 1"B=11.0093 amu. Round your answer to the nearest hundredth. (Hint: The sum of the fractional abundances is 1. If x=abundance of 1ºB, then 1-x= abundance of 11 B) % abundance of 10B = % % abundance of 11B =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Boron (B; Z=5) has two naturally occurring isotopes. Find the percent abundances of 10B and 11B given these data: atomic mass of B=10.81 amu, isotopic mass of 10B=10.0129 amu, and isotopic mass of 11B=11.0093 amu. Round your answer to the nearest hundredth.

(Hint: The sum of the fractional abundances is 1. If x=abundance of 10B, then 1-x= abundance of 11 B) 

Boron (B; Z=5) has two naturally occurring isotopes. Find the percent abundances of 10B and 11B given these data: atomic mass of B=10.81 amu, isotopic mass of 1ºB=10.0129 amu, and isotopic mass of 1"B=11.0093 amu. Round your answer to the nearest hundredth. (Hint: The sum of the fractional abundances is 1. If x=abundance of 1ºB, then 1-x= abundance of 11 B) % abundance of 10B = % abundance of 11B =
Transcribed Image Text:Boron (B; Z=5) has two naturally occurring isotopes. Find the percent abundances of 10B and 11B given these data: atomic mass of B=10.81 amu, isotopic mass of 1ºB=10.0129 amu, and isotopic mass of 1"B=11.0093 amu. Round your answer to the nearest hundredth. (Hint: The sum of the fractional abundances is 1. If x=abundance of 1ºB, then 1-x= abundance of 11 B) % abundance of 10B = % abundance of 11B =
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