Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A) B2S5 B B257 (© BS3 BS2

Boron and sulfur form two binary compounds. The first contains 0.2247 g B/1.000 g S, and the second contains 0.1348 g B/1.000 g S. If the formula for the first compound is a multiple of B2S3, then the second is a multiple of: (AW: ? ... B=10.811; S=32.065) A) B2S5 B B257 (© BS3 BS2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Boron and sulfur form two binary compounds. The first
contains 0.2247 g B/1.000 g S, and the second contains
0.1348 g B/1.000 g S. If the formula for the first compound
is a multiple of B2S3, then the second is a multiple of: (AW: ?
...
B=10.811; S=32.065)
A
B2S5
B257
(c) BS3
BS2

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