boolean iaPal (String s) { Show the Activation Stack for "ZEROREZ" if (enath ( ) == 0 || Eength () =- 1) 7/ if length =0 OR 1 then it is return true; if (sharAt (0) =- EcharAt (EuLenath ()-1)) 7/ check first and last char of String: // if same then do same for substring // for substring and carry on this // remove first and last char. return isPal ( string (1, tenath ()-1)); // if its not the case than string is not. return false:

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
icon
Related questions
Question

Java

Need the bottom half answered. 

What does Recursion Require?
1. Termination Condition
2. Call the Clone (same function)
3. Move towards Termination Condition
Label the Recursion Requirements.
Show the Activation Stack for n = 4.
int fact (int n)
{
int result;
if (n==1)
return 1;
result = fact (n-1) * n:
return result;
boolean isPal (String s)
Show the Activation Stack for "ZEROREZ"
if (s.length () -- 0 | 8.length ()
// if length =0 OR 1 then it is
return true;
if (charAt (0)
// check first and last char of String:
// if same then do same for substring
// for substring and carry on this
// remove first and last char.
return isPal (s.substring (1, 3.length ()-1));
1)
S.charAt (s.length ()-1))
// if its not the case than string is not.
return false;
}
Transcribed Image Text:What does Recursion Require? 1. Termination Condition 2. Call the Clone (same function) 3. Move towards Termination Condition Label the Recursion Requirements. Show the Activation Stack for n = 4. int fact (int n) { int result; if (n==1) return 1; result = fact (n-1) * n: return result; boolean isPal (String s) Show the Activation Stack for "ZEROREZ" if (s.length () -- 0 | 8.length () // if length =0 OR 1 then it is return true; if (charAt (0) // check first and last char of String: // if same then do same for substring // for substring and carry on this // remove first and last char. return isPal (s.substring (1, 3.length ()-1)); 1) S.charAt (s.length ()-1)) // if its not the case than string is not. return false; }
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Stack
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Database System Concepts
Database System Concepts
Computer Science
ISBN:
9780078022159
Author:
Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:
McGraw-Hill Education
Starting Out with Python (4th Edition)
Starting Out with Python (4th Edition)
Computer Science
ISBN:
9780134444321
Author:
Tony Gaddis
Publisher:
PEARSON
Digital Fundamentals (11th Edition)
Digital Fundamentals (11th Edition)
Computer Science
ISBN:
9780132737968
Author:
Thomas L. Floyd
Publisher:
PEARSON
C How to Program (8th Edition)
C How to Program (8th Edition)
Computer Science
ISBN:
9780133976892
Author:
Paul J. Deitel, Harvey Deitel
Publisher:
PEARSON
Database Systems: Design, Implementation, & Manag…
Database Systems: Design, Implementation, & Manag…
Computer Science
ISBN:
9781337627900
Author:
Carlos Coronel, Steven Morris
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Computer Science
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education