How do I fix this "implicit conversion loses integer precision: 'unsigned long' to 'int' " warning? 1112bool isPalindrome(string word) {1314for (int i = 0; i < word.size(); ++i)15{16if (wordI")==17return true;18for (int iword.size() - 1; j >= 0; --j)A Implicit conversion loses integer precision: 'unsi...19{20if (word.at(i) != word.at(j))21return false;2223}24return true;25 }

IMPLICIT CONVERSION: Implicit conversion is basically the conversion which is applied on the data…

bool isPalindrome(string word) { for (int i = 0; i < word.size(); ++i) { if (word == "") return true; for (int i = word.size) - 1; j >= 0; --j) A Implicit conversion loses integer precision: 'unsi.. { if (word.at(i) != word.at(j)) return false; } } return true; }

bool isPalindrome(string word) { for (int i = 0; i < word.size(); ++i) { if (word == "") return true; for (int i = word.size) - 1; j >= 0; --j) A Implicit conversion loses integer precision: 'unsi.. { if (word.at(i) != word.at(j)) return false; } } return true; }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }
#include <stdio.h>#include <string.h> int findRepeat(char* s){int p , i , j; p = -1; for (i = 0 ; i < strlen(s) ; i++){for (j = i + 1; j < strlen(s); j++){if (s[i] == s[j]){p = i;break;}}if (p != -1)break;}return p;} int main(){char str[] = "Hello World";int pos = findRepeat(str);if (pos == -1)printf("Not found");elseprintf("%c", str[pos]);return 0;}can you please explain this code for me
// Assume all libraries are included void QQ(int n); // int main () { // Random questions QQ (5) ; 3 4 6. 7 8. 9. 10 return 0; 11 } // void QQ(int n) 12 13 14 { if(n >= 1) { 15 16 17 cout << n; QQ (--n); } else 18 19 20 21 cout << n; 22 } // 23
double tab1[5] = {2,3,4,5,6}; double tab2[5] = {6,5,4,3,2}; for(int i = 0;i<5;i++) { tab1[i] = tab1[i]*tab2[i]; cout<<tab1[i]<<" "; } 12 15 16 15 16 15 15 16 15 12 12 15 16 15 12 12 15 12 15 12
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8
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