Bob selects independent random samples from two populations and obtains the values pi 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard error of pi – p2 (the ESE of the estimate). - Tom wants to estimate the mean of the success rates:
Bob selects independent random samples from two populations and obtains the values pi 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ±0.094. Note that 0.048 is called the estimated standard error of pi – p2 (the ESE of the estimate). - Tom wants to estimate the mean of the success rates:
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![27. Bob selects independent random samples from
two populations and obtains the values p1
0.700 and p2 = 0.500. He constructs the 95%
confidence interval for p1
P2 and gets:
|
0.200 + 1.96(0.048) = 0.200±0.094.
Note that 0.048 is called the estimated standard
error of pi – P2 (the ESE of the estimate).
Tom wants to estimate the mean of the success
rates:
Pi + P2
2
(a) Calculate Tom's point estimate.
(b) Given that the estimated standard er-
ror of (p1 + P2)/2 is 0.024, calculate
the 95% confidence interval estimate of
(p1 + P2)/2. Hint: The answer has our
usual form:
Pt. est. + 1.96 × ESE of the estimate.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F422241f2-a5fb-4cfd-9884-7cf3fa90750d%2F3eb51dac-0f6b-47d1-a866-a0e277ad3341%2F66x2anr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:27. Bob selects independent random samples from
two populations and obtains the values p1
0.700 and p2 = 0.500. He constructs the 95%
confidence interval for p1
P2 and gets:
|
0.200 + 1.96(0.048) = 0.200±0.094.
Note that 0.048 is called the estimated standard
error of pi – P2 (the ESE of the estimate).
Tom wants to estimate the mean of the success
rates:
Pi + P2
2
(a) Calculate Tom's point estimate.
(b) Given that the estimated standard er-
ror of (p1 + P2)/2 is 0.024, calculate
the 95% confidence interval estimate of
(p1 + P2)/2. Hint: The answer has our
usual form:
Pt. est. + 1.96 × ESE of the estimate.
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