Bob pushes on a frictionless cart of mass 6.9 kg and the cart has an acceleration of 7.7 m/s2. If Bob now pushes equally hard on a cart with twice the mass, what will be the acceleration of the heavier cart (in m/s²)? Your Answer: Answer
Bob pushes on a frictionless cart of mass 6.9 kg and the cart has an acceleration of 7.7 m/s2. If Bob now pushes equally hard on a cart with twice the mass, what will be the acceleration of the heavier cart (in m/s²)? Your Answer: Answer
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Physics Problem: Calculating Acceleration**
**Problem Statement:**
Bob pushes on a frictionless cart of mass 6.9 kg and the cart has an acceleration of 7.7 m/s². If Bob now pushes equally hard on a cart with twice the mass, what will be the acceleration of the heavier cart (in m/s²)?
**Your Answer:**
[Text Box for Answer]
**Explanation:**
This problem involves the relationship between force, mass, and acceleration described by Newton's Second Law of Motion. Newton's Second Law is given by the formula \( F = ma \), where \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration.
### Scenario Breakdown:
1. **Initial Situation:**
- **Mass**: 6.9 kg
- **Acceleration**: 7.7 m/s²
- From Newton’s Second Law \( F = ma \), we can find the force applied by Bob.
2. **When Mass is Doubled:**
- The new mass is \( 2 \times 6.9 \) kg = 13.8 kg.
- The force applied by Bob remains the same.
### Solution:
1. Calculate the force applied by Bob for the initial scenario.
2. Use the same force to find the new acceleration when the mass is doubled.
Using these steps will help in solving the problem and understanding the effect of mass on acceleration when the applied force is constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd99dc5ee-0347-4b7c-8511-9a91331fbdb4%2F08cbcf95-5790-4d42-8e2f-89768e8321c2%2Frcgbdhs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Problem: Calculating Acceleration**
**Problem Statement:**
Bob pushes on a frictionless cart of mass 6.9 kg and the cart has an acceleration of 7.7 m/s². If Bob now pushes equally hard on a cart with twice the mass, what will be the acceleration of the heavier cart (in m/s²)?
**Your Answer:**
[Text Box for Answer]
**Explanation:**
This problem involves the relationship between force, mass, and acceleration described by Newton's Second Law of Motion. Newton's Second Law is given by the formula \( F = ma \), where \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration.
### Scenario Breakdown:
1. **Initial Situation:**
- **Mass**: 6.9 kg
- **Acceleration**: 7.7 m/s²
- From Newton’s Second Law \( F = ma \), we can find the force applied by Bob.
2. **When Mass is Doubled:**
- The new mass is \( 2 \times 6.9 \) kg = 13.8 kg.
- The force applied by Bob remains the same.
### Solution:
1. Calculate the force applied by Bob for the initial scenario.
2. Use the same force to find the new acceleration when the mass is doubled.
Using these steps will help in solving the problem and understanding the effect of mass on acceleration when the applied force is constant.
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