Answered: A particle of mass 1.2 kg is acted on…

A particle of mass 1.2 kg is acted on by forces F, = 18î N, F, = -11î N, and F, = 9.0j N. What is its acceleration (in m/s?) in this case? (Express your answer in vector form.) m/s?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 4OQ: What is the y component of the vector (3i8k) m/s? (a) 3 m/s (b) 8 m/s (c) 0 (d) 8 m/s (e) none of...

See similar textbooks

Related questions

Q: An object's tendency to stay at rest or resist a change in motion. A. Interia B. Acceleration C.…

A: Newton gave three law's governing motion of objects .These law's are known as Newton's laws of…

Q: law x (1) q = 4 ms- A body of mass 2 kg travels according to the = pt + gi + rt where p = 3 ms- and…

Q: An object with mass 75 kg is pulled on a horizontal surface by a horizontal pull of 50 N to the…

A: Given: Mass, m=75 kg Applied Force, F=50 N right Friction force, f=30 N left Newton's second Law is…

Q: What force is required to accelerate an electron to 1.00 x 10^2 m/s?

A: Given : Acceleration of an electron (a) = 1.00 x 102 m/s2

Q: Two blocks of masses 2 kg and 1 kg are in contact with each other on a frictionless table. When a…

A: m2=2 kgm1=1 kgF=3 N

Q: What is the acceleration of an object with the force of 63N and a mass of 3 kg ? A 27 m/s^2 B 21…

Q: A 9000-N automobile is pushed along a level road by four students who apply a total forward force of…

A: Given data: Weight of the automobile (W) = 9000 N Force applied (F) = 500 N Friction force is…

Q: A boat with mass of 2.6 * 10° kg is traveling at 1.5 * 10' m/s. What is the magnitude of the force…

Q: A ball of mass 5 kg experiences a change in its velocity from 2 m/s to 4 m/s within 20 s, under the…

A: Given, m = 5 kg t = 20s u = 2 ms-1 v = 4 m/s

Q: What would our mass need to be if we wanted to reach an acceleration of 8 m/s 2 meters per squared…

Q: What will be its displacement after 5 s when a net force of 6 N acts upon an object with a mass of 2…

Q: "A 60-kg person walks on a 100-kg log at the rate of 0.80 m/s (with respect to the log). With what…

A: mass of person (m) = 60 kg mass of log (M) = 100 kg speed of person with repsect to log (v) = 0.80…

Q: Make a representation of the following vector quantities a. A velocity of 20m/s north b. A force of…

A: We have to make a representation of the following vector quantities a. A velocity of 20m/s north. b.…

Q: What will be its displacement after 5 s when a net force of 6 N acts upon an object with a mass of 2…

A: Given data: Time (t) = 5 s Force (F) = 6 N Mass (m) = 2 kg Initial velocity (v0) = 1 m/s Required:…

Q: 5,400 kg freight truck accelerates from 8 m/s to 43 m/s in 1.0 s by applying a constant force. How…

Q: Two forces F = -5.30i + 7.70j and F, = 9.20i + 7.40j are acting on an object with a mass of m = 7.90…

Q: A 4.0 kg object has a velocity of 3i m/s at one instant. Eight seconds later, its velocity is (8i +…

A: Write the first kinematic equation to determine the acceleration.

Q: When a constant force acts upon an object, the acceleration of the object varies inversely with its…

A: According to the Newton's second law Force = mass x acceleration

Q: A standard object defined as having a mass of exactly 4.6 kg is given an acceleration of 2.4169 m/s2…

A: Given data: Mass (m1) = 4.6 kg Acceleration (a1 ) = 2.4169 m/s2 Acceleration of unknown object a2 =…

Q: A car of mass 1371 kg accelerates from rest to 16.9 m/s in 5.17 s. How much force was required to do…

A: Given:- m=1371 Kg t= 5.17 s u= initial velocity= 0 m/s v= final velocity= 16.9 m/s Lets find the…

Q: Three forces acting on an object are given by F, = (-1.9î + 7.45j) N, F, = (4.70î - 1.5j) N, and F,…

A: F1→ = -1.9i^ + 7.45j^ F2→ = 4.70i^ - 1.5j^ F3→ = 42i^ acceleration a = 4.00 m /s2 To find =…

Q: How long would it take for a net upward force of 100.0 N to increase the velocity of a 50-kg object…

A: Force is mass times acceleration. Force and mass is given acceleration can be found using Newton's…

Q: You throw a metal block of mass 0.19 kg into the air, and it leaves your hand at time t= 0 at…

A: Given: Mass of metal block = 0.19 kg Initial position = <0,2,0> m Initial velocity =…

Q: an object is lying on a table and its weight is 3N, what is the normal force equal to?

Q: Three vector forces F1, F2 and F3 act on a particle of mass m = 3.80 kg as shown in Fig. Calculate…

Q: The velocity of a body of mass 20 kg increases from 5 m/s to 20 m/s in a distance of 100 m. The…

Q: In applying the equation W = (F cos(?))d to the upward force, which of the following expressions is…

A: Given data The equation for work done is given as W=Fcosθd. The force force F is applied in an…

Q: When a force of 10N is applied to a body its acceleration is 2m/sz. The mass of the body is 5kg aO…

A: Answer:- (a) 5 kg Given Force (F) = 10 N Acceleration of a body(a) = 2 m/s2 Mass of a body (…

Q: An object with a mass of 2.0kg is accelerated at 5.0m/s/s.The net force acting on the mass is?

A: Given Data: The mass of an object is, m=2.0 kg The acceleration of an object is, a=5.0 m/s2 The…

Q: A 1.5-kg mass has an acceleration of (4.0i ^ − 3.0j ^ ) m/s2. Only two forces act on the mass. If…

A: Given: The mass of the object is 1.5 kg. The acceleration of the object is 4.0i^-3.0j^ m/s2. The one…

Q: A 2 kg otter starts from rest at the top of a muddy incline to 85 cm long and slides down to the…

Q: A 1500 kg car is pushed with 3000 N of net force from rest to a final velocity of 28 m/s. How far…

Q: Ella, with a mass 50.0 kg, is standing inside an elevator going up. The normal force of the floor on…

A: Given Mass of Ella = 50.0 kg Normal force = 755 N We have to find the magnitude of her upward…

Q: A box with mass 25.1 kg has an initial velocity of 2.66 m/s when a woman starts pushing the box with…

A: Given data: Mass of box is, m=25.1 kg. Initial velocity of box is, u=2.66 m/s. Net force acting on…

Q: A car with a mass of 1,450.0 kg accelerates from 0 to 73.0 km/h in 11.0 s. (Enter the magnitudes.)…

Q: A 1000.0 kg car accelerates uniformly to double its speed from 13.7 m/s in 4.76 s. What net force…

A: Given data: Mass of the car m =1000.0 kg speed, u =13.7 m/s Time t =4.76 s

Q: A 71.2 kg high jumper leaves the ground with a vertical velocity of 5.9 m/s. How high can he jump?…

Q: A net force of 15 N exerted on a wooden block produces an acceleration of 5 m/s. The mass of the…

Q: Each of the three barges has a mass of 30 Mg, whereas the tugboat has a mass of 12 Mg. As the barges…

Q: If it takes a human cannonball 1.8 s to exit a 1.9 m long cannon and the average net force acting on…

A: Given, Length of the cannon, L = 1.9 m time taken by cannonball to exit, t = 1.8 s Net force acting…

Q: When a constant force is applied to an object, the acceleration of the object varies inversely with…

Q: The force that produces an acceleration of 1 m over s squared in a body of the mass of 2 kg is…

A: Given : a = 1 m/s2 m = 2 kg

Q: . How long would it take for a net upward force of 150 N, to increase the speed of a 40.0 kg object…

Question

A particle of mass 1.2 kg is acted on by forces F, = 18î N, F, = -11î N, and F, = 9.0j N. What is its acceleration (in m/s?) in this case? (Express your answer in vector form.)
m/s?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Similar questions

Two forces act on a 3.40 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (5.701 - 3.30ĵ) m. Write the second force in unit vector notation. (Enter your answer in kg. m/s². Assume the gravitational force acts in the -ĵ direction.) F = 13.2 X
The acceleration of a particle is a constant. At t=0 the velocity of the particle is (14.91 + 18.4ĵ) m/s. At t = 4.6 s the velocity is 11.4j m/s. (Use the following as necessary: t. Do not include units in your answers.) (a) What is the particle's acceleration (in m/s²)? = î+ 18.4 v(t) = (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin. r(t) = î+ X Î- i) m/s m/s
6.00k, with t in seconds and r in meters. An electron's position is given by 7 = 4.00tî – 5.00t2 ĵ + (a) In unit-vector notation, what is the electron's velocity v (t)? (Use the following as necessary: t.) V (t) = m/s (b) What is v in unit-vector notation at t = 5.00 s? v(t = 5.00) = m/s (c) What is the magnitude of v at t = 5.00 s? m/s (d) What angle does v make with the positive direction of the x axis at t = 5.00 s? ° (from the +x axis)
Two forces act on a 2.50 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (5.50î – 3.30j) m. Write the second force in unit vector notation. (Enter your answer in kg · m/s. Assume the gravitational force acts in the -ĵ direction.) kg · m/s2 II
The muzzle velocity of a typical 500 g spud is 25 m/s . The force given by the spud is K/(x+.09) where x is the distance of the barrel in meters. If the length of the barrel is 75 cm, what is the constant K? What is the force on the spud?
Ex. 12. Find the value of G from the following data : M = 6 x 1024 kg, R= 6400 km, g = 9.774 m/s? %3D %3D
A car traveling at 20 m/sm/s runs out of gas while traveling up a 9.0 degree slope. How far will it coast before starting to roll back down? Express your answer in meters.
Two forces act on a 2.90 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (4.10 3.30ĵ) m. Write the second force in unit vector notation. (Enter your answer in kg. m/s². Assume the gravitational force acts in the -ĵ direction.) kg. m/s² F
A constant applied force of 46.0 N lifts an 2.50 kg mass straight up resulting in a final speed of 4.8 m/s. what distance did the mass move if it was initially at rest?
A 2 kg ball is thrown off a 73 m high cliff with a speed of 4 m/s. How fast (in m/s) is the ball going when it hits the ground? Use g = 9.8 m/s2.
The block has mass m = 6.8 kg, the ramp is at an angle of θ = 28 degrees, the coefficient of kinetic friction between the block and the ramp is μk = 0.25, and the applied force is F = 156.4 N. What is the acceleration of the block up the ramp, in m/s2?
A ball dropped from a height of 30 cm, takes 0.6067 s to reach the ground. What is the acceleration due to gravity (g) at that place in S.I. units ? Select one: a. 0.988 b. 9.8 С. 163 O d. 1.63