Bob pushes on a frictionless cart of mass 6.8 kg and the cart has an acceleration of 5.7 m/s2. If Bob now pushes twice as hard on a cart with twice the mass, what will be the acceleration of the heavier cart? Your Answer:

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**Problem:**

Bob pushes on a frictionless cart of mass 6.8 kg, and the cart has an acceleration of 5.7 m/s². If Bob now pushes twice as hard on a cart with twice the mass, what will be the acceleration of the heavier cart?

**Solution:**

To find the acceleration of the heavier cart when Bob pushes twice as hard, we follow these steps:

Given:
- Initial mass of the cart (m₁) = 6.8 kg
- Acceleration of the cart (a₁) = 5.7 m/s²
- Force exerted by Bob (F) = m₁ * a₁

We need to determine:
- The acceleration (a₂) of the new cart with twice the mass when Bob pushes with twice the force.

Step-by-step calculation:

1. Calculate the force Bob initially exerts:
   \[ F = m₁ \cdot a₁ = 6.8 \text{ kg} \cdot 5.7 \text{ m/s}^2 = 38.76 \text{ N} \]

2. If Bob pushes twice as hard, the force will be:
   \[ F_{\text{new}} = 2 \cdot F = 2 \cdot 38.76 \text{ N} = 77.52 \text{ N} \]

3. The new cart has twice the mass:
   \[ m₂ = 2 \cdot m₁ = 2 \cdot 6.8 \text{ kg} = 13.6 \text{ kg} \]

4. Using Newton's second law, calculate the acceleration (a₂) of the heavier cart:
   \[ a₂ = \frac{F_{\text{new}}}{m₂} = \frac{77.52 \text{ N}}{13.6 \text{ kg}} \]

5. Compute the result:
   \[ a₂ = 5.7 \text{ m/s}^2 \]

Thus, the acceleration of the heavier cart will be \( 5.7 \text{ m/s}^2 \).
Transcribed Image Text:**Problem:** Bob pushes on a frictionless cart of mass 6.8 kg, and the cart has an acceleration of 5.7 m/s². If Bob now pushes twice as hard on a cart with twice the mass, what will be the acceleration of the heavier cart? **Solution:** To find the acceleration of the heavier cart when Bob pushes twice as hard, we follow these steps: Given: - Initial mass of the cart (m₁) = 6.8 kg - Acceleration of the cart (a₁) = 5.7 m/s² - Force exerted by Bob (F) = m₁ * a₁ We need to determine: - The acceleration (a₂) of the new cart with twice the mass when Bob pushes with twice the force. Step-by-step calculation: 1. Calculate the force Bob initially exerts: \[ F = m₁ \cdot a₁ = 6.8 \text{ kg} \cdot 5.7 \text{ m/s}^2 = 38.76 \text{ N} \] 2. If Bob pushes twice as hard, the force will be: \[ F_{\text{new}} = 2 \cdot F = 2 \cdot 38.76 \text{ N} = 77.52 \text{ N} \] 3. The new cart has twice the mass: \[ m₂ = 2 \cdot m₁ = 2 \cdot 6.8 \text{ kg} = 13.6 \text{ kg} \] 4. Using Newton's second law, calculate the acceleration (a₂) of the heavier cart: \[ a₂ = \frac{F_{\text{new}}}{m₂} = \frac{77.52 \text{ N}}{13.6 \text{ kg}} \] 5. Compute the result: \[ a₂ = 5.7 \text{ m/s}^2 \] Thus, the acceleration of the heavier cart will be \( 5.7 \text{ m/s}^2 \).
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