Bill and Joann fight over a shiny new frictionless wagon with a mass of 11.8 kg. If Joann is pulling left with 121 N of force, and the wagon has an acceleration of 3.29 m/s² to the right, how hard is Bill pulling (to the right) on the wagon? Your Answer: Answer

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**Physics Problem:**

**Scenario:**
Bill and Joann fight over a shiny new frictionless wagon with a mass of 11.8 kg. If Joann is pulling left with 121 N of force, and the wagon has an acceleration of 3.29 m/s² to the right, how hard is Bill pulling (to the right) on the wagon?

**Calculated Force:**  
To find out how hard Bill is pulling, we need to consider the forces acting on the wagon and apply Newton's Second Law (F = ma).

Given data:
- Mass of the wagon (m) = 11.8 kg
- Joann's pulling force (F₁) = 121 N to the left (negative direction)
- Acceleration (a) = 3.29 m/s² to the right (positive direction)

Let's denote Bill's force as F₂ (to the right).

Using the formula F_net = m * a, where F_net is the net force acting on the wagon:
F_net = F₂ - F₁

Plugging in the given values:
m * a = F₂ - F₁
11.8 kg * 3.29 m/s² = F₂ - (-121 N)

F₂ = (11.8 kg * 3.29 m/s²) + 121 N

Simplify the multiplication:
F₂ = (38.822 N) + 121 N
F₂ = 159.822 N

**Answer:**  
Bill is pulling with a force of approximately 159.8 N to the right on the wagon.

**Your Answer:**  
[Answer box for user input]
Transcribed Image Text:**Physics Problem:** **Scenario:** Bill and Joann fight over a shiny new frictionless wagon with a mass of 11.8 kg. If Joann is pulling left with 121 N of force, and the wagon has an acceleration of 3.29 m/s² to the right, how hard is Bill pulling (to the right) on the wagon? **Calculated Force:** To find out how hard Bill is pulling, we need to consider the forces acting on the wagon and apply Newton's Second Law (F = ma). Given data: - Mass of the wagon (m) = 11.8 kg - Joann's pulling force (F₁) = 121 N to the left (negative direction) - Acceleration (a) = 3.29 m/s² to the right (positive direction) Let's denote Bill's force as F₂ (to the right). Using the formula F_net = m * a, where F_net is the net force acting on the wagon: F_net = F₂ - F₁ Plugging in the given values: m * a = F₂ - F₁ 11.8 kg * 3.29 m/s² = F₂ - (-121 N) F₂ = (11.8 kg * 3.29 m/s²) + 121 N Simplify the multiplication: F₂ = (38.822 N) + 121 N F₂ = 159.822 N **Answer:** Bill is pulling with a force of approximately 159.8 N to the right on the wagon. **Your Answer:** [Answer box for user input]
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