*Boat is the more stable conformation of cyclopentane -1 Benzoin can be prepared from reaction benzaldehyde with acetone -2 The enone can be prepared from Mannich reaction -3 Q/true or false • The benzilic acid rearrangement containing 1.2-methyl shift -4 OH IUPAC name of this compound is 1-hydroxy decaline Trot The product for reaction between 2 mole of benzaldehyde in KCN is -6 *1,2-diphenyl-ethan-2-ol-1-one The Robenson anulation including Michael reaction and -7 * Intramolecular aldol condensation

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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*Boat is the more stable conformation of cyclopentane -1
Benzoin can be prepared from reaction benzaldehyde with acetone -2
The enone can be prepared from Mannich reaction-3
Q/true or false
*The benzilic acid rearrangement containing 1.2-methyl shift -4
OH
IUPAC name of this compound
is 1-hydroxy decaline
thote The product for reaction between 2 mole of benzaldehyde in KCN is -6
* 1,2-diphenyl-ethan-2-ol-1-one
The Robenson anulation including Michael reaction and -7
* Intramolecular aldol condensation
Transcribed Image Text:*Boat is the more stable conformation of cyclopentane -1 Benzoin can be prepared from reaction benzaldehyde with acetone -2 The enone can be prepared from Mannich reaction-3 Q/true or false *The benzilic acid rearrangement containing 1.2-methyl shift -4 OH IUPAC name of this compound is 1-hydroxy decaline thote The product for reaction between 2 mole of benzaldehyde in KCN is -6 * 1,2-diphenyl-ethan-2-ol-1-one The Robenson anulation including Michael reaction and -7 * Intramolecular aldol condensation
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