Block X and Y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block X is 10 kg and that of block Y is 5 kg. The magnitude of force of friction on blocks X and Y is 8.0 N and 4.0 N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N [right] acts on block X. block y ------- block x -> 40 N (Fa) a) The force of X on Y is 14 N [right] and the force of Y on X is 14 N [left] b) The force of X on Y is 12 N [right] and the force of Y on X is 14 N [left] c) The force of X on Y is 7.4 N [right] and the force of Y on X is 4.1 N [left] d) The force of X on Y is 22 N [right] and the force of Y on X is 22 N [left]

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”