**Problem Statement:**A block is supported by two cables as shown in the schematic. The tension in cable CB is 50 N.**Tasks:**a) Draw the free body diagram and kinetic diagrams of the point C that the three cables are connected to.b) Determine the tension in cable CA.c) Determine the mass of the block.---**Explanation:**1. **Free Body Diagram:** - A diagram should be drawn showing point C where three cables intersect. - Indicate forces acting along the cables with the given tension in cable CB as 50 N. - The directions of these forces must be clearly shown with vectors.2. **Determining Tension in Cable CA:** - Utilize equilibrium equations to calculate the tension in cable CA. - Use the known tension in cable CB (50 N) in your calculations.3. **Determining Mass of the Block:** - Apply principles of equilibrium and possibly Newton’s laws to compute the mass. - Consider gravitational forces acting on the block.As the schematic is not provided in the image, ensure to assume clarity and direction of forces consistent with typical mechanics problems when illustrating the diagram. The image shows a mechanics diagram illustrating the forces at play in a pulley system with two support points, labeled A and B, connected by cords to a third point, C. The system supports a weight at point C, exerting a downward force.- **Pulley System:** - **Point A**: The cord at A is angled 42 degrees below the horizontal. - **Point B**: The cord at B forms a 23-degree angle with the vertical dashed line. - **Point C**: This is the junction where the cords from points A and B connect and where the weight is suspended.- **Forces:** - The weight at point C results in a force vector of 50 Newtons acting vertically downward.This setup is typically used to demonstrate principles of static equilibrium, tension in cords, and vector resolution of forces.

since object is in equilibrium we can apply lamis theorem FCBsin90+42=FACsin180-23=mgsin48+23 Fcb=50

Block is supported by two cables as shown in the schematic. Tension in the cable CB is 50 N. a) Draw the free body diagram and kinetic diagrams of the point C that the three cables are connected to. b) Determine the tension in cable CA. c) Determine the mass of the block.

Block is supported by two cables as shown in the schematic. Tension in the cable CB is 50 N. a) Draw the free body diagram and kinetic diagrams of the point C that the three cables are connected to. b) Determine the tension in cable CA. c) Determine the mass of the block.

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Problem Statement:**

A block is supported by two cables as shown in the schematic. The tension in cable CB is 50 N.

**Tasks:**

a) Draw the free body diagram and kinetic diagrams of the point C that the three cables are connected to.

b) Determine the tension in cable CA.

c) Determine the mass of the block.

---

**Explanation:**

1. **Free Body Diagram:**
- A diagram should be drawn showing point C where three cables intersect.
- Indicate forces acting along the cables with the given tension in cable CB as 50 N.
- The directions of these forces must be clearly shown with vectors.

2. **Determining Tension in Cable CA:**
- Utilize equilibrium equations to calculate the tension in cable CA.
- Use the known tension in cable CB (50 N) in your calculations.

3. **Determining Mass of the Block:**
- Apply principles of equilibrium and possibly Newton’s laws to compute the mass.
- Consider gravitational forces acting on the block.

As the schematic is not provided in the image, ensure to assume clarity and direction of forces consistent with typical mechanics problems when illustrating the diagram.

The image shows a mechanics diagram illustrating the forces at play in a pulley system with two support points, labeled A and B, connected by cords to a third point, C. The system supports a weight at point C, exerting a downward force.

- **Pulley System:**
- **Point A**: The cord at A is angled 42 degrees below the horizontal.
- **Point B**: The cord at B forms a 23-degree angle with the vertical dashed line.
- **Point C**: This is the junction where the cords from points A and B connect and where the weight is suspended.

- **Forces:**
- The weight at point C results in a force vector of 50 Newtons acting vertically downward.

This setup is typically used to demonstrate principles of static equilibrium, tension in cords, and vector resolution of forces.

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