Block A supports a pipe column and rests as shown on wedge B. Knowing that the coefficient of static friction at all surfaces of contact is 0.25 and that e - 45degrees, determine the smallest force P required to raise block A. 3 kN B O 9.76 kN O 9.56 kN O 9.86 kN O 9.96 kN O 9.66 kN

Q: Replace the two forces and single couple by an equivalent force-couple system at point A. 15 KN A 37…

A: to find equivalent couple force system at point A

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A: To find moment at point A

Q: Calculate the support reactions at pins A and D when; a.) H=0 b.) H= 14 13 kN/m H C B 1-21 4 m 8m

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Q: for the simply supported beam shown. The = (maximum value of shear force (V 2m 50 KN 10 m 50 kN 2m…

A: Given : simply supported beam Load W= 50 kN at  2m from support To determine: maximum shear force

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A: Consider the figure,

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Q: cylinder is in 1. Determine the moment of this 4.4-kN force about the boom pivot point O. The moment…

A: ##Calculation of moment about pivot point O due to 4.4 KN ###

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Q: Untitled Section F1= 10 kN F2 = 26 kN 8- 45 45 F3 =8 KN B 4 m F4= 44 kN E La-45 FS = 8 kN 1] What is…

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Q: What is the support moment M, in the beam shown below? 15KN 30 kN/m -1.5 m 1.5 m

A: UVL of 30 KN/m for 1.5 m lengthA concentrated load of 15 KN at the end of beamCorrect option is…

Q: Find: a. b. c. Situation 4: Considering the beam provided below, fixed support at point A, an…

A: As per guidelines, first three sub parts have been solved.

Q: Block A supports a pipe column and rests as shown on wedge B. Knowing that the coefficient of static…

A:

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Q: Determine fixed support reaction . I will upvote Give fast answer

A: FBD :

Q: Boom BC, as shown, supports a load of 15 kN which is then mainly supported by cable AB. The boom…

A: Data given:A = 1990 mm2x(bar) = 12.7mmIx = 6.29×106 mm4Iy = 0.358×106 mm4rx=56.4 mmry=13.4 mmloads =…

Q: st 1.5 kN 1 kN 4 m

A: solution first find the reactions at the supports consider ∑Fy=0 and consider  ∑Fx=0 Py+Ty=3KN…

Q: H-W The coefficient of static friction μ, between the 100-kg body and the 15° wedge is 0.20.…

A: Step 1: Step 2: Step 3:

Q: O2 A |B C| 1.5 m--1.5 m 1.5 m -|

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Q: F1 5 KN F2 13 kN e-45 P60 F3 4 kN 4 m 8 m F4 = 22 kN a 30 F5 = 4 kN 1] What is the resultant moment…

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Q: Question 6 E F D 225 kN 6 m A B 6 m 6 m Using Cantilever Method, determine the Shear force at EF in…

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Q: Name four zero force members in the Figure. 6 kN 900 N- 2 m 2 m SE B.

A: Given- Trus s diagram with different loads

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Q: Determine the internal force carried by member CD. 50 kN 50 kN 100 kN 4 m B 3 m

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Q: If the coefficient of static friction at all contacting surfaces is µ,, determine the inclination 0…

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Q: 2.5 m D A 20 KN 3 m E B 40 kN 3 m C 40 kN

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Q: Determine the internal force carried by member AB. 50 kN 50 kN 100 kN 4 m B 3 m

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Q: 2 kN 2 m В 2 m 2 m 3 m 4 kN E O 8.94 kN (C) O 8.00 kN (T) O 8.94 kN (T) O NONE OF THE GIVEN CHOICES…

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Q: Q5: Determine the resultant and position of the resultant force from point C 3 KN 30 to 02 m 03m 5KN…

A: Solution Determine the resultant

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Q: 3) The 4 KN load is hoisted at a constant speed using motor M, which has a weight of 0.45 KN.…

A: Load hoisted on the motor = 4kNWeight of motor = 0.45 kNSelf-weight of the beam = 0.6 kN/m

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Q: celeration of the center B of the pulley for the following conditions: 0 = 16°, Ô0 = 6 deg/sec, Ö =…

A: Givenθ=16 degθ˙=6 deg/secθ¨=6 deg/sec2l=6ftl˙=2.2 ft/secl¨=-3.5 ft/sec2

Q: A beam is loaded with a uniformly distributed load between the two roller supports and a single load…

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Q: H.W. Determine the horizontal and vertical components of force at pins A and D. D. Ans A, = 24.0 kN…

A: The FBD of the beam:

Q: Untitled Section F1 = 5 kN F2 = 13 kN C. F3 4 kN 45° 60 2 m 7 m F4 = 22 kND EJu= 30 FS = 4 KN 1]…

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Q: Determine support reaction

A: The given beam is determinate beam hence he apply equilibrium condition to solve the support…