Block A of mass 60 kg, tied to the wall by a cable, is resting on Block B of mass 100 kg as shown. An unknown horizontal force P is applied at Block B such that it is about to cause impending motion of Block B down the inclined plane of 30°. The coefficient of frictions are given as shown. Cable 60 kg H = 0.4 100 kg H,= 0.3 30° Figure 3.1 38MEF (a) Draw the free body diagram of Block A and Block B. [T = 498.2 N] (b) Determine the tension in the cable. (c) Determine the force P to cause impending motion of Block B down the inclined plane. [P = 121.19 N]

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Block A of mass 60 kg, tied to the wall by a cable, is resting on Block B of mass 100 kg as shown. An
unknown horizontal force P is applied at Block B such that it is about to cause impending motion of
Block B down the inclined plane of 30°. The coefficient of frictions are given as shown.
Cable
60 kg
H = 0.4
100 kg
P.
H=0.3
30°.-
Figure 3.1
38MEF
(a) Draw the free body diagram of Block A and Block B.
(b) Determine the tension in the cable.
(c) Determine the force P to cause impending motion of Block B down the inclined plane.
[T = 498.2 N]
[P = 121.19 N]
Transcribed Image Text:Block A of mass 60 kg, tied to the wall by a cable, is resting on Block B of mass 100 kg as shown. An unknown horizontal force P is applied at Block B such that it is about to cause impending motion of Block B down the inclined plane of 30°. The coefficient of frictions are given as shown. Cable 60 kg H = 0.4 100 kg P. H=0.3 30°.- Figure 3.1 38MEF (a) Draw the free body diagram of Block A and Block B. (b) Determine the tension in the cable. (c) Determine the force P to cause impending motion of Block B down the inclined plane. [T = 498.2 N] [P = 121.19 N]
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