Block 1, of mass m1m1m_1 = 6.30 kgkg , moves along a frictionless air track with speed v1v1v_1 = 17.0 m/sm/s . It collides with block 2, of mass m2m2m_2 = 37.0 kgkg , which was initially at rest. The blocks stick together after the collision. (Figure 1)What is the change ΔK=Kfinal−KinitialΔK=Kfinal−Kinitial in the two-block system's kinetic energy due to the collision?Express your answer numerically in joules. the answer is not 778778.27 Review T ConstanCorrectBlock 1, of mass m1 = 6.30 kg , moves along a frictionless airtrack with speed v1 = 17.0 m/s . It collides with block 2, of massm2 = 37.0 kg , which was initially at rest. The blocks sticktogether after the collision. (Figure 1)Part BFind vf , the magnitude of the final velocity of the two-block system.Express your answer numerically.• View Available Hint(s)Vf = 2.47 m/sSubmitPrevious Answersv CorrectPart CWhat is the change AK = Kinal – Kinitial in the two-block system's kinetic energy due to the collision?Express your answer numerically in joules.Figure1 of 1• View Available Hint(s)ΑΣΦ?Before collision:m2m12AK = |778J1SubmitPrevious Answers Request AnswerAfter collision:X Incorrect; Try Again; 3 attempts remaining1Provide FeedbackNex

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Description: Block 1, of mass m1m1m_1 = 6.30 kgkg , moves along a frictionless air track with speed v1v1v_1 = 17.0 m/sm/s . It collides with block 2, of mass m2m2m_2 = 37.0 kgkg , which was initially at rest. The blocks stick together after the collision. (Figure

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Block 1, of mass m1m1m_1 = 6.30 kgkg , moves along a frictionless air track with speed v1v1v_1 = 17.0 m/sm/s . It collides with block 2, of mass m2m2m_2 = 37.0 kgkg , which was initially at rest. The blocks stick together after the collision. (Figure 1)

What is the change ΔK=Kfinal−KinitialΔK=Kfinal−Kinitial in the two-block system's kinetic energy due to the collision?

Express your answer numerically in joules.

the answer is not

778

778.27

Review T Constan
Correct
Block 1, of mass m1 = 6.30 kg , moves along a frictionless air
track with speed v1 = 17.0 m/s . It collides with block 2, of mass
m2 = 37.0 kg , which was initially at rest. The blocks stick
together after the collision. (Figure 1)
Part B
Find vf , the magnitude of the final velocity of the two-block system.
Express your answer numerically.
• View Available Hint(s)
Vf = 2.47 m/s
Submit
Previous Answers
v Correct
Part C
What is the change AK = Kinal – Kinitial in the two-block system's kinetic energy due to the collision?
Express your answer numerically in joules.
Figure
1 of 1
• View Available Hint(s)
ΑΣΦ
?
Before collision:
m2
m1
2
AK = |778
J
1
Submit
Previous Answers Request Answer
After collision:
X Incorrect; Try Again; 3 attempts remaining
1
Provide Feedback
Nex

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