Block 1, of mass m1 = 3.30 kg , moves along a frictionless air track with speed v1 = 13.0 m/s. It collides with block 2, of mass m2 = 45.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Find the magnitude pi of the total initial momentum of the two-block system. Express your answer numerically. ? Pi = 87.9 kg m/s Submit Request Answer Part B Figure 1 of 1 Find vr, the magnitude of the final velocity of the two-block system.

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Chapter1: Units, Trigonometry. And Vectors
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I think I got A and B but not sure if they're correct. Can you please help with C and look at A & B? Thanks

Block 1, of mass m1 = 3.30 kg , moves along a frictionless
air track with speed v1 = 13.0 m/s. It collides with block
2, of mass m2 = 45.0 kg , which was initially at rest. The
blocks stick together after the collision. (Figure 1)
Find the magnitude pi of the total initial momentum of the two-block system.
Express your answer numerically.
Pi = 87.9
kg - m/s
Submit
Request Answer
Part B
Figure
(< 1 of 1
Find vr, the magnitude of the final velocity of the two-block system.
Before collision:
Express your answer numerically.
m2
2
?
Vf = |1.82
m/s
After collision:
Submit
Request Answer
2
Transcribed Image Text:Block 1, of mass m1 = 3.30 kg , moves along a frictionless air track with speed v1 = 13.0 m/s. It collides with block 2, of mass m2 = 45.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Find the magnitude pi of the total initial momentum of the two-block system. Express your answer numerically. Pi = 87.9 kg - m/s Submit Request Answer Part B Figure (< 1 of 1 Find vr, the magnitude of the final velocity of the two-block system. Before collision: Express your answer numerically. m2 2 ? Vf = |1.82 m/s After collision: Submit Request Answer 2
Block 1, of mass m1 = 3.30 kg , moves along a frictionless
air track with speed v = 13.0 m/s. It collides with block
2, of mass m2 = 45.0 kg , which was initially at rest. The
blocks stick together after the collision. (Figure 1)
Find vr, the magnitude of the final velocity of the two-block system.
Express your answer numerically.
vf = 1.82
m/s
Submit
Request Answer
Part C
Figure
1 of 1 >
What is the change AK = Kfinal – Kinitial in the two-block system's kinetic energy due to the collision?
Before collision:
Express your answer numerically in joules.
m2
2
AK =
After collision:
Submit
Request Answer
2
1
Transcribed Image Text:Block 1, of mass m1 = 3.30 kg , moves along a frictionless air track with speed v = 13.0 m/s. It collides with block 2, of mass m2 = 45.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) Find vr, the magnitude of the final velocity of the two-block system. Express your answer numerically. vf = 1.82 m/s Submit Request Answer Part C Figure 1 of 1 > What is the change AK = Kfinal – Kinitial in the two-block system's kinetic energy due to the collision? Before collision: Express your answer numerically in joules. m2 2 AK = After collision: Submit Request Answer 2 1
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