Block 1 (14 kg) is located on the surface of a table. A rope pulls on block 1 with a tension of 119.2 N at an angle of 67.30 degrees above the horizontal. The coefficient of kinetic friction between the block and the surface equals 0.6 (Use g = 10 m/s2). On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Tension force on block 1 by Rope (rounded to nearest integer) T1R = i + j N Normal force on block 1 by Surface N1S = i + j N Frictional force on block 1 by Surface f1S = i + j N Tries 0/2
Block 1 (14 kg) is located on the surface of a table. A rope pulls on block 1 with a tension of 119.2 N at an angle of 67.30 degrees above the horizontal. The coefficient of kinetic friction between the block and the surface equals 0.6 (Use g = 10 m/s2).
On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component.
FORCES on BLOCK 1
Weight force on block 1 by Earth
W1E = i + j N
Tension force on block 1 by Rope (rounded to nearest integer)
T1R = i + j N
Normal force on block 1 by Surface
N1S = i + j N
Frictional force on block 1 by Surface
f1S = i + j N
| Tries 0/2 |
What is the acceleration a of block 1?
a = i + j m/s2
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
