Black Holes - The supermassive black hole imaged by the Event Horizon Telescope (EHT) is one of the largest black holes in the nearby Universe. At a distance of 55 million light years from Earth, and with a mass equal to 2.4e12 solar masses, calculate the angular diameter of that black hole's event horizon as viewed from the Earth. (express your answer in arcseconds)
Black Holes - The supermassive black hole imaged by the Event Horizon Telescope (EHT) is one of the largest black holes in the nearby Universe. At a distance of 55 million light years from Earth, and with a mass equal to 2.4e12 solar masses, calculate the angular diameter of that black hole's event horizon as viewed from the Earth. (express your answer in arcseconds)
The points in the space that are very dense and forms deep sinks for gravity are called black holes. The gravitational field of such black holes is very intense that even the light which have such a huge speed can't pass through them.
The diameter of the black hole's event Horizon telescope is given by,
G= the gravitational constant having value , c= speed of the light having value , and M is the black hole's mass. It is given the mass of the black hole is 2.4e12 solar masses. As, 1 solar mass= . So, on calculating its mass in the kilograms, we get,
M=
So on putting the values on the above formula, the diameter obtained is,
d=
We know the angular distance in radians is calculated by the formula,
R is the distance from the earth to the black hole=55 million light-years. We know, One light year= . So,
R=
Thus, the angular diameter is,
For converting radians to arc seconds, we will multiply it by
so,
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