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бх + бу + 52z = 2 6x + (26 – k)y + 4z = 4 %3D 6x + 6y + (7 – k)z = k + 18 a) X1 Suppose the above equation is expressed as Ax = b with x = x2 . Express the X3 coeffieints of the equations in one matrix form as (A|b)= 6. 6. 6. 6. 2)

бх + бу + 52z = 2 6x + (26 – k)y + 4z = 4 %3D 6x + 6y + (7 – k)z = k + 18 a) X1 Suppose the above equation is expressed as Ax = b with x = x2 . Express the X3 coeffieints of the equations in one matrix form as (A|b)= 6. 6. 6. 6. 2)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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6х + бу + 5z = 2 6x + (26 – k)y + 4z = 4 6x + 6y + (7 – k)z = k + 18 a) X1 Suppose the above equation is expressed as Ax = b with x = X2 . Express the X3 coeffieints of the equations in one matrix form as (A|b )= 6. 6. 6. 6.
Transcribed Image Text:6х + бу + 5z = 2 6x + (26 – k)y + 4z = 4 6x + 6y + (7 – k)z = k + 18 a) X1 Suppose the above equation is expressed as Ax = b with x = X2 . Express the X3 coeffieints of the equations in one matrix form as (A|b )= 6. 6. 6. 6.
b) Use row operations on (A|b) by substracting row 1 from row 2 and row 3 respectively. Fill in the missing entries: 6. c) If the equations have no solution, determine the value of k =
Transcribed Image Text:b) Use row operations on (A|b) by substracting row 1 from row 2 and row 3 respectively. Fill in the missing entries: 6. c) If the equations have no solution, determine the value of k =
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