Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
I want the best value for percent purity and how did you arrive at the best value
![**Part II: Synthesized Aspirin**
**Trial 1**
- Mass of aspirin (g): 0.486 g
- Theoretical moles: 2.70 x 10^-3 mol
**Trial 2**
- Mass of aspirin (g): 0.485 g
- Theoretical moles: 2.69 x 10^-3 mol
**Calculations for Theoretical Moles:**
- **Trial 1:**
- \(0.486 \, \text{g asp} \times \frac{1.00 \, \text{mol}}{180.16 \, \text{g asp}} = 2.70 \times 10^{-3} \, \text{mol}\)
- **Trial 2:**
- \(0.485 \, \text{g asp} \times \frac{1.00 \, \text{mol}}{180.16 \, \text{g asp}} = 2.69 \times 10^{-3} \, \text{mol}\)
**Molarity of NaOH:**
- 0.216 mol/L
**Volume of NaOH used (mL):**
- **Trial 1:** 11.85 mL
- **Trial 2:** 12.99 mL
**Color of Solution:**
- **Trial 1:** Medium/dark pink color
- **Trial 2:** Darker pink color than Trial 1
**Moles of NaOH used:**
- **Trial 1:** 0.00256 moles NaOH
- **Trial 2:** 0.0028 moles NaOH
**Calculations for Moles of NaOH:**
- **Trial 1:** \(0.216 \, \text{mol/L} \times 0.01185 \, \text{L NaOH} = 0.00256 \, \text{moles NaOH}\)
- **Trial 2:** \(0.216 \, \text{mol/L} \times 0.01299 \, \text{L NaOH} = 0.0028 \, \text{moles NaOH}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d353b8f-29b7-4b65-b20b-402aa69a76cb%2F72f362bd-6429-48d7-87a5-d06521400f50%2F68abgj8.jpeg&w=3840&q=75)
Transcribed Image Text:**Part II: Synthesized Aspirin**
**Trial 1**
- Mass of aspirin (g): 0.486 g
- Theoretical moles: 2.70 x 10^-3 mol
**Trial 2**
- Mass of aspirin (g): 0.485 g
- Theoretical moles: 2.69 x 10^-3 mol
**Calculations for Theoretical Moles:**
- **Trial 1:**
- \(0.486 \, \text{g asp} \times \frac{1.00 \, \text{mol}}{180.16 \, \text{g asp}} = 2.70 \times 10^{-3} \, \text{mol}\)
- **Trial 2:**
- \(0.485 \, \text{g asp} \times \frac{1.00 \, \text{mol}}{180.16 \, \text{g asp}} = 2.69 \times 10^{-3} \, \text{mol}\)
**Molarity of NaOH:**
- 0.216 mol/L
**Volume of NaOH used (mL):**
- **Trial 1:** 11.85 mL
- **Trial 2:** 12.99 mL
**Color of Solution:**
- **Trial 1:** Medium/dark pink color
- **Trial 2:** Darker pink color than Trial 1
**Moles of NaOH used:**
- **Trial 1:** 0.00256 moles NaOH
- **Trial 2:** 0.0028 moles NaOH
**Calculations for Moles of NaOH:**
- **Trial 1:** \(0.216 \, \text{mol/L} \times 0.01185 \, \text{L NaOH} = 0.00256 \, \text{moles NaOH}\)
- **Trial 2:** \(0.216 \, \text{mol/L} \times 0.01299 \, \text{L NaOH} = 0.0028 \, \text{moles NaOH}\)
![**Percent Purity of Aspirin (%):**
- **99.41**
**Example Calculation:**
\[ \frac{0.4833 \, \text{g asp}}{0.4862} \times 100 = 99.41\% \]
**Best Value for % Purity:**
__________________
**How did you arrive at the best value?**
__________________
**Part III - Commercial Aspirin**
- **Trial 1:**
- **Mass of Aspirin Tablet (g):**
\[ 0.371g \]
- **Theoretical Moles in Tablet:**
\[ 2.06 \times 10^{-3} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d353b8f-29b7-4b65-b20b-402aa69a76cb%2F72f362bd-6429-48d7-87a5-d06521400f50%2Fmmkhipe.jpeg&w=3840&q=75)
Transcribed Image Text:**Percent Purity of Aspirin (%):**
- **99.41**
**Example Calculation:**
\[ \frac{0.4833 \, \text{g asp}}{0.4862} \times 100 = 99.41\% \]
**Best Value for % Purity:**
__________________
**How did you arrive at the best value?**
__________________
**Part III - Commercial Aspirin**
- **Trial 1:**
- **Mass of Aspirin Tablet (g):**
\[ 0.371g \]
- **Theoretical Moles in Tablet:**
\[ 2.06 \times 10^{-3} \]
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