besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? The byte offset needs 5 bits to address each byte offset because 2^5 = 32, (b) How many bits are used for the set (index) field? 13 bits for the set (index) (c) How many bits are used for the tag? 32-13-5=14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits_ (e) How is the address divided, label below?
besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? The byte offset needs 5 bits to address each byte offset because 2^5 = 32, (b) How many bits are used for the set (index) field? 13 bits for the set (index) (c) How many bits are used for the tag? 32-13-5=14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits_ (e) How is the address divided, label below?
Chapter11: Operating Systems
Section: Chapter Questions
Problem 30VE
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is part e corrrect and please explain
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