besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? The byte offset needs 5 bits to address each byte offset because 2^5 = 32, (b) How many bits are used for the set (index) field? 13 bits for the set (index) (c) How many bits are used for the tag? 32-13-5=14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits_ (e) How is the address divided, label below?
besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block. Calculate the following: (a) How many bits are used for the byte offset and why? The byte offset needs 5 bits to address each byte offset because 2^5 = 32, (b) How many bits are used for the set (index) field? 13 bits for the set (index) (c) How many bits are used for the tag? 32-13-5=14 bits_ (d) What's the overhead for that cache? 2^13 X 14 = 114688 bits_ (e) How is the address divided, label below?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
is part e corrrect and please explain
![1
besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block.
Calculate the following:
(a) How many bits are used for the byte offset and why?
The byte offset needs 5 bits to address each byte offset because 2^5 = 32
(b) How many bits are used for the set (index) field?
3
0
13 bits for the set (index)__
(c) How many bits are used for the tag?
32-13-5= 14 bits_
(d) What's the overhead for that cache?
2^13 X 14 = 114688 bits_
(e) How is the address divided, label below?
8
7
Tag [31-10]
2
1
2 1
1
0 9 8
7
1
6
1
5
4
3
HE
0
Index [9-5}
m
2 1
block [4 - 0]
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe00f331-3f4e-4e17-853e-c4aa2122c265%2F9210b5c0-9aab-4c6c-8719-9d143c3a22b0%2Fvwpbtcq_processed.png&w=3840&q=75)
Transcribed Image Text:1
besign a 256KB (note the B) direct-mapped data cache that uses 32-bit data and address and 8 words per block.
Calculate the following:
(a) How many bits are used for the byte offset and why?
The byte offset needs 5 bits to address each byte offset because 2^5 = 32
(b) How many bits are used for the set (index) field?
3
0
13 bits for the set (index)__
(c) How many bits are used for the tag?
32-13-5= 14 bits_
(d) What's the overhead for that cache?
2^13 X 14 = 114688 bits_
(e) How is the address divided, label below?
8
7
Tag [31-10]
2
1
2 1
1
0 9 8
7
1
6
1
5
4
3
HE
0
Index [9-5}
m
2 1
block [4 - 0]
0
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