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below. A smaller square chunk was cut from the square block, leaving a hole in the figure. Find the center of mass of the composite figure. Use the axes provided as reference for the origin (0, 0).

below. A smaller square chunk was cut from the square block, leaving a hole in the figure. Find the center of mass of the composite figure. Use the axes provided as reference for the origin (0, 0).

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Shape Area Center of mass A h bh h ar² 4r 4 h h(b + 2a' (a + b)h ỹ = 3 b+a Shape of area Distance Distance Area y a Square G Rectangle ab Circle 4r 3.7 Ar Semi-circle 2 bh Right-angled triangle 3 2 S I3 II II
Transcribed Image Text:Shape Area Center of mass A h bh h ar² 4r 4 h h(b + 2a' (a + b)h ỹ = 3 b+a Shape of area Distance Distance Area y a Square G Rectangle ab Circle 4r 3.7 Ar Semi-circle 2 bh Right-angled triangle 3 2 S I3 II II
A square block, a rectangular block, a triangular block, and a quarter circle block are arranged as shown below. A smaller square chunk was cut from the square block, leaving a hole in the figure. Find the center of mass of the composite figure. Use the axes provided as reference for the origin (0, 0). Square: L units x L units, mass = m Rectangle: (L/2) units x 2L units, mass = 3.5 m Quarter circle: radius = (L/2) units, mass = 5 m Triangle: height = L units, base = (L/2) units, mass = 0.75 m Square hole: L/2 units x L/2 units %3D
Transcribed Image Text:A square block, a rectangular block, a triangular block, and a quarter circle block are arranged as shown below. A smaller square chunk was cut from the square block, leaving a hole in the figure. Find the center of mass of the composite figure. Use the axes provided as reference for the origin (0, 0). Square: L units x L units, mass = m Rectangle: (L/2) units x 2L units, mass = 3.5 m Quarter circle: radius = (L/2) units, mass = 5 m Triangle: height = L units, base = (L/2) units, mass = 0.75 m Square hole: L/2 units x L/2 units %3D
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