Below is a table that shows samples of computed p values and the corresponding level of significance, a (alpha). Put the appropriate remarks whether to reject Ho or to accept Ho. Ho is your null hypothesis. Computed p-value Interpretation Level of Significance a 1. p= 0.07 2. p=0.00 3. p = 0.05 a =0.05 a =0.05 a =0.05
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- A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…A researcher wants to test whether the mean height for men and women are different, using a significance level of 0.05. Which is the correct hypothesis? A Ho: P1 = P2 Ha: P1 P2 D Ho: P1 = μ2 Ha: H1 H2 O C A OF OE O B B Ho: P1 = P2 Ha: P1 P2 E Ho: P1 = μ2 Ha: 12 C Ho: P1 = P2 Ha: 1: P₁ P2 F H₂:₁ = 1₂ Ha: ₁ 2D Question 24 The weights of cats is Normally Distributed. The mean weight is 10 lbs with a standard deviation of 0.2 lbs. Draw the normal curve and fill in the cut scores and percentages. Then answer the questions below: Based on a sample of 600 cats, how many would you expect to weigh more than 10.4 lbs? Based on a sample of 600 cats, how many would you expect to weigh at least 9.8 lbs. but not more than 10.2 lbs? Based on a sample of 600 cats, how many would you expect to weigh more than 10 lbs?
- The mean ACT score for 43 male high school students is 21.1 and the standard deviation is 5.0. The mean ACT score for 56 female high school students is 20.9 and the standard deviation is 4.7. At the 1% significance level, can you reject the claim that male and female high school students have equal ACT score averages? Be sure to use the p-value to make your conclusion.Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"Use the following R output to answer the question. Use the following R output to answer the question. >chisq.test(data) Pearsons Chi-square test data:data X-squared=4.7194, df=2, p-value=0.09445 If the significance level is 5%, what conclusion can you make? Group of answer choices A. fail to reject the alternative hypothesis B. cannot determine C. fail to reject the null hypothesis D. reject the null hypothesis and accept the alternative hypothesis
- You may need to use the appropriate technology to answer this question. Submitted The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B C P 20 44 50 Q 30 26 30 Test for independence of the row and column variables using a = 0.05. State the null and alternative hypotheses. Ho: The column variable is independent of the row variable. H: The column variable is not independent of the row variable. Ho: Variable P is not independent of variable Q. H: Variable P is independent of variable Q. Ho: Variable P is independent of variable Q. H: Variable P is not independent of variable Q. : The column variable is not independent of the row variable. Ho: : The column variable is independent of the row variable. Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value %3D State your conclusion. Reject Ho. We conclude that the column and row variables are…Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 = 0 E. Ho: Hd 0 Ha: Hd s0 The test statistic is t= 1.43 . (Round to two decimal places as needed.) The critical value(s) is(are) to = (Round to two decimal places as needed. Use a comma to separate answers as needed.)Please sir or ma’am, please help me with hypothesis, critical region, and t statistic.
- Data for fuel economy ratings in mi/gal for different cars are listed below. Each pair of data represents the rating using the Old test and the New test. Old (x) 31 22 23 33 27 21 22 19 31 16 New (y) 25 17 26 26 23 18 19 16 28 19 Find the best predicted value for the New test method given that the Old test method rating was 26. Use a significance level of 0.05.Round your answer to 1 decimal place, if needed.You wish to test the following claim (HaHa) at a significance level of α=0.02α=0.02. Ho:μ=70.6Ho:μ=70.6 Ha:μ≠70.6Ha:μ≠70.6You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 113.7 91.9 98.1 112.8 What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 70.6. There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 70.6. The sample data support the claim that the…Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…