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Below is a passive high-pass RC filter. The value of the capacitor, C, is 2 nF (nanofarads) and the resistance value, R, is 3,000 2. What is the gain value at a frequency f = 4,000 Hz. Present your answer in decibels (dB). Hints: (1) Recall that "gain" (or attenuation) is calculated as A = Vo/V₁, and the corresponding value in decibels is A = 20 log10 (Vo/Vi); (2) The angular frequency is calculated as w = 2πf. Vi ㅓ다 ww R Vo

Below is a passive high-pass RC filter. The value of the capacitor, C, is 2 nF (nanofarads) and the resistance value, R, is 3,000 2. What is the gain value at a frequency f = 4,000 Hz. Present your answer in decibels (dB). Hints: (1) Recall that "gain" (or attenuation) is calculated as A = Vo/V₁, and the corresponding value in decibels is A = 20 log10 (Vo/Vi); (2) The angular frequency is calculated as w = 2πf. Vi ㅓ다 ww R Vo

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Below is a passive high-pass RC filter. The value of the capacitor, C, is 2 nF (nanofarads) and the resistance value, R, is 3,000 Ω. What is the gain value at a frequency ? = 4,000 Hz. Present your answer in decibels (dB).

5. Below is a passive high-pass RC filter. The value of the capacitor, C, is 2 nF (nanofarads) and the resistance value, R, is 3,000 . What is the gain value at a frequency f = 4,000 Hz. Present your answer in decibels (dB). Hints: (1) Recall that “gain" (or attenuation) is calculated as A = Vo/V₁, and the corresponding value in decibels is A = 20 log₁0 (Vo/Vi); (2) The angular frequency is calculated as w = 2πƒ. Vi Ich ww R Vo
Transcribed Image Text:5. Below is a passive high-pass RC filter. The value of the capacitor, C, is 2 nF (nanofarads) and the resistance value, R, is 3,000 . What is the gain value at a frequency f = 4,000 Hz. Present your answer in decibels (dB). Hints: (1) Recall that “gain" (or attenuation) is calculated as A = Vo/V₁, and the corresponding value in decibels is A = 20 log₁0 (Vo/Vi); (2) The angular frequency is calculated as w = 2πƒ. Vi Ich ww R Vo
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