Below is a graph of a normal distribution with mean μ = 4 and standard deviation o=2. The shaded regionrepresents the probability of obtaining a value from this distribution that is between 5 and 7.0.4+0.3+0.2+0.1+4Shade the corresponding region under the standard normal curve below.0.40.3+0.2+0.1+X

For the stated normal distribution, it is given that:The mean, μ=4The standard deviation, σ=2.The…

Answered: Below is a graph of a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Scores on the SAT exam approximate a normal distribution with a mean of 600 and a standard deviation of 80. Use the distribution to determine (z- score must be rounded to the two decimal places): The z-score for a SAT score of 470 The percent of SAT scores that fall above 750 The probability for a SAT score that fall below 800 The percentage of SAT scores that fall between 525 and 570
Normal Distributions According to the Center for Disease Control, young adult women have an average systolic blood pressure of 114.8 with a standard deviation of 13.1. Systolic blood pressure for young adult women follows a normal distribution. Four young adult women were randomly selected, find the probability that their average systolic blood pressure is greater than 125. P(I > 125) = For this problem, we were told that the distribution is normal. If the shape of the distribution was not stated, we would not have been able to use the normal distribution table to find the probability. What does the Central Limit Theorem tell us to do to be able to normalize the distribution? It cannot be normalized What is the rule of thumb for normalizing the sampling distribution of means? np 2 10 and ng 2 10 + Please answer all parts of the question.
The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. u = 3.26 (a) What is the minimum UGPA that would still place a student in the top 5% of UGPAS? o = 0.22 (b) Between what two values does the middle 50% of the UGPAS lie? 2.52 3.26 4 Grade point average (a) The minimum UGPA that would still place a student in the top 5% of UGPAS is (Round to two decimal places as needed.)
answer please
Scores on the Math Achievement Test form a normal distribution with a mean of μ = 300 and σ = 100. A school distributes scholarships to students who score in the top 10% for this test. What score or higher must be earned to score in the top 10% on the Math Achievement Test?
IQ scores form a normal distribution with a mean of μ =25 and a standard deviation of σ = 12. Find the z-score for X= 30 and a sample of n = 89 people?
Find the probabilities for each, using the standard normal distribution. Shade the area of the region under the normal curve.
Use a table of cumulative areas under the normal curve to find the z-score that corresponds to the given cumulative area. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. 0.053 The cumulative area corresponds to the z-score of ____. (round to 3 decimal places as needed)
The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAS? (b) Between what two values does the middle 50% of the UGPAS lie? 2.48 3.24 Grade point average (a) The minimum UGPA that would still place a student in the top 15% of UGPAs is 3.41. (Round to two decimal places as needed.) H=3.24 0.16 (b) The middle 50% of UGPAS lies between on the low end and on the high end. (Round to two decimal places as needed.) Q G
(a) The graph shows a Standard Normal Distribution. You are given 1 or 2 z-score(s) and need to shade the area (=probability) corresponding to: P(z > 1.2). Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. Then slide the arrow to the appropriate z-score. Shade: Left of a value Click and drag the arrows to adjust the values. -4 -3 -2 -1 2 4 -1.5 (b) Part 2: you are given an area (=probability), and you need to compute c, which is the z-score that corresponds to the statement: P( - c < z < c) (This is an inverse standard normal distribution problem. Use technology to compute c) The arrow can only be dragged to tick marks that are multiples of 0.1 So, round c to 1 decimal place, and then move the arrow to that rounded value. Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. (If the question is less c, choose Left of a…
Below is a graph of a normal distribution with mean u = -3 and standard deviation o =2. The shaded region represents theprobability of obtaining a value from this distribution that is between -4 and 0. Shade the corresponding region under the standard normal curve below.

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