Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. ● NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ +4e-> 2H₂O (+0.82 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-¹ to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron acceptor. ● NO₂ + 6e-> NH4+ (+0.34 volts) • O₂ +4e-> 2H₂O (+0.82 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are oxidized. Finally, use the simplified Nernst Equation AG = -nFAE, where F = 96.5 kJ (mol e x V)-¹ to determine the Gibbs Free energy available to do work! • Report your answer in kJ rounded to two decimal places. o Include trailing zeros!! Always report two decimal places even if the answer is a whole number o e.g. 18.00 not 18 • Report only the numeric portion of your answer o e.g. 1.01, not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energy and oxygen is the terminal electron
acceptor.
NO₂ + 6e-> NH4+ (+0.34 volts)
• O₂ + 4e -> 2H₂O (+0.82 volts)
●
Using the information given, calculate the AE for this reaction, balance the full reaction to determine the n, the number of electrons transferred when 30 moles of NH4* are
oxidized. Finally, use the simplified Nernst Equation
AG = -nFAE, where F = 96.5 kJ (mol e x V)-1
to determine the Gibbs Free energy available to do work!
• Report your answer in kJ rounded to two decimal places.
o Include trailing zeros!! Always report two decimal places even if the answer is a whole number
o e.g. 18.00 not 18
• Report only the numeric portion of your answer
o e.g. 1.01, not 1.01 kj per mole.
• Answers should ALWAYS be negative since this is a spontaneous reaction.
Type your answer...

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