Below are the paired reduction reactions for chemolithotrophic denitrification: these organisms are using nitrate as an electron accepter and are using hydrogen gas as a source of energy and electrons. 2NO₂+ 10e-> N₂ (+0.74 volts) 2H+ 2e-> H₂ (-0.42 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determine n, the number of electrons transfered when 142 moles of Hy are oxidized. Finally, use the simplified Nernst Equation AG-nFAE. where F-96.5 kJ (exV)¹ to determine the Gibbs Free energy available to do work! • Report your answer in kJ in standard decimal notation rounded to two decimal places, Including trailing zeros, even if it is a whole number eg. 18.00, not 18. Report only the numeric portion of your answer eg. 1.01. not 1.01 kj per mole. • Answers should ALWAYS be negative since this is a spontaneous reaction

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Below are the paired reduction reactions for chemolithotrophic denitrification: these organisms are using nitrate as an electron accepter and are using hydrogen
gas as a source of energy and electrons.
2NO₂+ 10e-> N₂ (+0.74 volts)
2H+2e-> H₂ (-0.42 volts)
Using the information given, calculate the AE for this reaction, balance the full reaction to determinen, the number of electrons transfered when 142 moles
of H₂ are oxidized. Finally, use the simplified Nernst Equation
AG-nFAE, where F-96,5 kJ (ex V) ¹
to determine the Gibbs Free energy available to do work!
Report your answer in kJ in standard decimal notation rounded to two decimal places,
Including trailing zeros, even if it is a whole number
eg. 18.00, not 18
Report only the numeric portion of your answer
e.g. 1.01. not 1.01 kj per mole.
Answers should ALWAYS be negative since this is a spontaneous reaction.
Type your answer...
Transcribed Image Text:32 Below are the paired reduction reactions for chemolithotrophic denitrification: these organisms are using nitrate as an electron accepter and are using hydrogen gas as a source of energy and electrons. 2NO₂+ 10e-> N₂ (+0.74 volts) 2H+2e-> H₂ (-0.42 volts) Using the information given, calculate the AE for this reaction, balance the full reaction to determinen, the number of electrons transfered when 142 moles of H₂ are oxidized. Finally, use the simplified Nernst Equation AG-nFAE, where F-96,5 kJ (ex V) ¹ to determine the Gibbs Free energy available to do work! Report your answer in kJ in standard decimal notation rounded to two decimal places, Including trailing zeros, even if it is a whole number eg. 18.00, not 18 Report only the numeric portion of your answer e.g. 1.01. not 1.01 kj per mole. Answers should ALWAYS be negative since this is a spontaneous reaction. Type your answer...
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