Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon. CO₂ + 8e -> CH3COO™ (E° = -0.29 volts) 504²+8e-> H₂S (EO = -0.22 volts) If you balance and combine the reactions so that 180 moles of CH3COO™ are oxidized to CO₂, how many moles of H₂S will be produced? • Report your answer in standard decimal notation rounded to two decimal places. • Include trailing zeros, even if the answer is a whole number o e.g. 18.00, not Report only the numeric part of your answer o e.g. 18.00, not 18.00 moles H₂S
Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon. CO₂ + 8e -> CH3COO™ (E° = -0.29 volts) 504²+8e-> H₂S (EO = -0.22 volts) If you balance and combine the reactions so that 180 moles of CH3COO™ are oxidized to CO₂, how many moles of H₂S will be produced? • Report your answer in standard decimal notation rounded to two decimal places. • Include trailing zeros, even if the answer is a whole number o e.g. 18.00, not Report only the numeric part of your answer o e.g. 18.00, not 18.00 moles H₂S
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Below are the half reactions for sulfate reduction using acetate as a source of electrons, energy, and carbon.
CO₂ + 8e -> CH3COO™ (E° = -0.29 volts)
504²+8e-> H₂S (EO = -0.22 volts)
If you balance and combine the reactions so that 180 moles of CH3COO™ are oxidized to CO₂, how many moles of H₂S will be produced?
• Report your answer in standard decimal notation rounded to two decimal places.
•
Include trailing zeros, even if the answer is a whole number
o e.g. 18.00, not
Report only the numeric part of your answer
o e.g. 18.00, not 18.00 moles H₂S
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