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Below are the elementary steps are proposed for a mechanism, what is the balanced chemical equation and the molecularity of each step, and write the rate law for the fifth step. * 2NO(g) 2H,(g) (3) N„O2(g) + H(g) (4) HO(g) + H(g) (5) H(g) + N,O(g) N,O2(8) 4H(g) N20(g) + HO(g) H,O(g) HO(g) + N,(g) (1) (2) – O 2NO(g) + 2H2(g) -> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [H][N2O] O NO(g) + H2(g) --> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [N20] 2NO(g) + 2H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N2O] NO(g) + H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N2O] %3D

Below are the elementary steps are proposed for a mechanism, what is the balanced chemical equation and the molecularity of each step, and write the rate law for the fifth step. * 2NO(g) 2H,(g) (3) N„O2(g) + H(g) (4) HO(g) + H(g) (5) H(g) + N,O(g) N,O2(8) 4H(g) N20(g) + HO(g) H,O(g) HO(g) + N,(g) (1) (2) – O 2NO(g) + 2H2(g) -> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [H][N2O] O NO(g) + H2(g) --> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [N20] 2NO(g) + 2H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N2O] NO(g) + H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N2O] %3D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Below are the elementary steps are proposed for a mechanism, what is the balanced chemical equation and the molecularity of each step, and write the rate law for the fifth step.

Below are the elementary steps are proposed for a mechanism, what is the balanced chemical equation and the molecularity of each step, and write the rate law for the fifth step. * N,O2(g) 4H(g) N,0(8) + HO(g) H,O(g) HO(g) + N,(8) 2NO(g) 2H,(8) (1) (2) (3) N,O2(g) + H(g) (4) HO(g) + H(g) (5) H(g) + N,O(g) 2NO(g) + 2H2(g) --> N2(g) + 2H20(g); all are bimolecular;, rate5 = k5 [H][N20] NO(g) + H2(g) --> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [N20] 2NO(g) + 2H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N20] NO(g) + H2(g) --> N2(g) + 2H20(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N20] %3D
Transcribed Image Text:Below are the elementary steps are proposed for a mechanism, what is the balanced chemical equation and the molecularity of each step, and write the rate law for the fifth step. * N,O2(g) 4H(g) N,0(8) + HO(g) H,O(g) HO(g) + N,(8) 2NO(g) 2H,(8) (1) (2) (3) N,O2(g) + H(g) (4) HO(g) + H(g) (5) H(g) + N,O(g) 2NO(g) + 2H2(g) --> N2(g) + 2H20(g); all are bimolecular;, rate5 = k5 [H][N20] NO(g) + H2(g) --> N2(g) + 2H2O(g); all are bimolecular; rate5 = k5 [N20] 2NO(g) + 2H2(g) --> N2(g) + 2H2O(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N20] NO(g) + H2(g) --> N2(g) + 2H20(g); step 2 is unimolecular while the others are bimolecular; rate5 = k5 [H][N20] %3D
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