52. For a bimolecular elementary reaction, why does the reaction rate depend on the product of the reactant concentrations? Give a very simple example, using numbers, to illustrate your answer. 53. Why is there no such thing as a trimolecular elementary reaction?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
100%
### Chemical Kinetics: Understanding Elementary Reactions

#### 52. For a bimolecular elementary reaction, why does the reaction rate depend on the product of the reactant concentrations? Give a very simple example, using numbers, to illustrate your answer.

**Explanation:**
In a bimolecular elementary reaction, two reactant molecules collide and react to form products. The rate of such reactions depends on how frequently the reactant molecules collide with each other, which in turn depends on their concentrations. Mathematically, the rate \( r \) of a bimolecular reaction involving reactants \( A \) and \( B \) can be expressed as:

\[ r = k[A][B] \]

Where:
- \( k \) is the rate constant.
- \([A]\) and \([B]\) are the concentrations of reactants A and B respectively.

**Example:**
Suppose \( [A] = 2 \) M and \( [B] = 3 \) M, and the rate constant \( k = 1 \, \text{L} \cdot \text{mol}^{-1} \cdot \text{s}^{-1} \).

Then, the reaction rate \( r \) can be calculated as:

\[ r = (1 \, \text{L} \cdot \text{mol}^{-1} \cdot \text{s}^{-1})(2 \, \text{M})(3 \, \text{M}) = 6 \, \text{M}^2 \cdot \text{L}^{-1} \cdot \text{s}^{-1} \]

This illustrates that the reaction rate is proportional to the product of the concentrations of \( A \) and \( B \).

#### 53. Why is there no such thing as a trimolecular elementary reaction?

**Explanation:**
In chemical kinetics, elementary reactions involve a small number of reactant molecules colliding simultaneously. While bimolecular reactions (involving two molecules) are quite common, trimolecular reactions (involving three molecules colliding simultaneously) are extremely rare. The reason is purely probabilistic: the likelihood of three molecules coming together at the exact same moment with the proper orientation and sufficient energy to react is very low. Such events are statistically unlikely in a typical chemical environment.

Instead, reactions that appear to involve three or more molecules usually proceed via a series of simpler bimolecular or unimolecular
Transcribed Image Text:### Chemical Kinetics: Understanding Elementary Reactions #### 52. For a bimolecular elementary reaction, why does the reaction rate depend on the product of the reactant concentrations? Give a very simple example, using numbers, to illustrate your answer. **Explanation:** In a bimolecular elementary reaction, two reactant molecules collide and react to form products. The rate of such reactions depends on how frequently the reactant molecules collide with each other, which in turn depends on their concentrations. Mathematically, the rate \( r \) of a bimolecular reaction involving reactants \( A \) and \( B \) can be expressed as: \[ r = k[A][B] \] Where: - \( k \) is the rate constant. - \([A]\) and \([B]\) are the concentrations of reactants A and B respectively. **Example:** Suppose \( [A] = 2 \) M and \( [B] = 3 \) M, and the rate constant \( k = 1 \, \text{L} \cdot \text{mol}^{-1} \cdot \text{s}^{-1} \). Then, the reaction rate \( r \) can be calculated as: \[ r = (1 \, \text{L} \cdot \text{mol}^{-1} \cdot \text{s}^{-1})(2 \, \text{M})(3 \, \text{M}) = 6 \, \text{M}^2 \cdot \text{L}^{-1} \cdot \text{s}^{-1} \] This illustrates that the reaction rate is proportional to the product of the concentrations of \( A \) and \( B \). #### 53. Why is there no such thing as a trimolecular elementary reaction? **Explanation:** In chemical kinetics, elementary reactions involve a small number of reactant molecules colliding simultaneously. While bimolecular reactions (involving two molecules) are quite common, trimolecular reactions (involving three molecules colliding simultaneously) are extremely rare. The reason is purely probabilistic: the likelihood of three molecules coming together at the exact same moment with the proper orientation and sufficient energy to react is very low. Such events are statistically unlikely in a typical chemical environment. Instead, reactions that appear to involve three or more molecules usually proceed via a series of simpler bimolecular or unimolecular
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Rate Laws
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY