20. Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To findthe 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of theremaining values. Use the axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmedmean, and 20% trimmed mean.248 260 268 272 277 278 281 283 283 285286 289 290 290 292 295 297 299 312 501Identify any outliers. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.A. The outlier(s) is/arepounds.(Type a whole number. Use a comma to separate answers as needed.)B. There are no outliers.The median ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The untrimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The 10% trimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The 20% trimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.) Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To findthe 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of theremaining values. Use the axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmedmean, and 20% trimmed mean.248 260 268 272 277 278 281 283 283 285286 289 290 290 292 295 297 299 312 501Identify any outliers. Select the correct choice below and, if necessary, fill in the answer box to complete your choice.A. The outlier(s) is/arepounds.(Type a whole number. Use a comma to separate answers as needed.)B. There are no outliers.The median ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The untrimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The 10% trimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.)The 20% trimmed mean ispounds.(Type an integer or decimal rounded to one decimal place as needed.)

Given data set 248 260 268 272 277 278 281 283 283 285 286 289 290 290…

Because the mean is very sensitive to extreme values, it is not a resistant measure of center. By deleting some low values and high values, the trimmed mean is more resistant. To find the 10% trimmed mean for a data set, first arrange the data in order, then delete the bottom 10% of the values and delete the top 10% of the values, then calculate the mean of the remaining values. Use the axial loads (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any outliers, then compare the median, mean, 10% trimmed mean, and 20% trimmed mean. 248 260 268 272 277 278 281 283 283 285 286 289 290 290 292 295 297 299 312 501