Because the coating is expensive, you want to use a layer that has the minimum thickness possible, which you determine to be 104nm. What should the index of refraction of the coating be if it must cancel 550 nm light that hits the coated surface at normal incidence?

Because the coating is expensive, you want to use a layer that has the minimum thickness possible, which you determine to be 104nm. What should the index of refraction of the coating be if it must cancel 550 nm light that hits the coated surface at normal incidence?

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Two waves of light in air, of wavelength 600.0 nm, are initially in phase. They then travel through plastic layers as shown in the figure below, with L1 = 4.44 µm, L2 = 3.97 µm, n1 = 1.45, and n2 = 1.62. What multiple of A gives their phase difference after they have both emerged from the layers? Give absolute value. L1 Number i 0.906 Units This answer has no units
light of wavelength λ in a vacuum has a wavelength of 438 nm in water (n=1.33) and a wavelength of 390 nm in benzene. a) what is the wavelength λ? b) using only the given wavelengths, determine the ratio of the index of refraction of benzene to that of water.
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Figure P24.69 shows d- radio-wave transmitter and a receiver, both h = 50.0 m above the ground and d = 6.00 X 102 m apart. The receiver can receive signals directly from the transmit- ter and indirectly from signals that bounce off the ground. If the ground is level between the transmitter and receiver and a /2 phase shift occurs upon reflection, determine the longest wave- lengths that interfere (a) constructively and (b) destructively. Transmitter Receiver Figure P24.69
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A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with the wavelength of light and there is a phase shift at the top surface. If it becomes dark when the path length difference is less than one-fourth the wavelength, what is the thickest the oil can be and appear dark at all visible wavelengths? Oil has an index of refraction of 1.40. Take 380 nm to be the shortest visible wavelength in air.
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You stretch a strand of your hair across a laser beam and observe the diffraction pattern this produces on a sheet of paper 1.15 m from your hair strand. You mark the center of the dark regions on either side of the central bright spot and measure the distance between these marks to be 21.4 mm. You are given that the wavelength of the laser light is 633 nm. What is the diameter of your hair strand (in mm)? Make use of the small angle approximation. (Hint: recall Babinet's principle which equates the spot pattern created by light going around the hair to the pattern when light goes through a slit.)
Ch26,P24