) Because f(-1) and f' changes from negative to positive at x = f(-1) = -7e-1 is a local (and absolute) minimum.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Example 3: Sketch the graph of \( f(x) = 7xe^x \).**

**(A)** The domain of \( f \) is \(\mathbb{R}\).

**(B)** The x- and y-intercepts are both ______.

**(C)** Symmetry: None.

**(D)** Because both \( 7x \) and \( e^x \) become large as \( x \to \infty \), we have \( \lim_{x \to \infty} 7xe^x = \infty \). As \( x \to -\infty \), however, \( e^x \to 0 \) and so we have an indeterminate product that requires the use of l'Hospital's Rule:
\[
\lim_{x \to -\infty} 7xe^x = \lim_{x \to -\infty} \frac{7x}{e^{-x}} = \lim_{x \to -\infty} \frac{7}{-7e^{-x}} = \lim_{x \to -\infty} -7e^x = 0.
\]
Thus the x-axis is a horizontal asymptote.

**(E)** \( f'(x) = 7xe^x + 7e^x = ______ \)

Since \( e^x \) is always positive, we see that \( f'(x) > 0 \) when \( x + 1 > 0 \), and \( f'(x) < 0 \) when \( x + 1 < 0 \). So \( f \) is increasing on \( (______, \infty) \) and decreasing on \( (-\infty, ______) \).

**(F)** Because \( f'(-1) = 0 \) and \( f' \) changes from negative to positive at \( x = ______ \), \( f(-1) = -7e^{-1} \) is a local (and absolute) minimum.

**(G)** \( f''(x) = (7 + 7x)e^x + 7e^x = ______ \)

Since \( f''(x) > 0 \) if \( x > ______ \) and \( f''(x) < 0 \) if \( x < ______ \), \( f
Transcribed Image Text:**Example 3: Sketch the graph of \( f(x) = 7xe^x \).** **(A)** The domain of \( f \) is \(\mathbb{R}\). **(B)** The x- and y-intercepts are both ______. **(C)** Symmetry: None. **(D)** Because both \( 7x \) and \( e^x \) become large as \( x \to \infty \), we have \( \lim_{x \to \infty} 7xe^x = \infty \). As \( x \to -\infty \), however, \( e^x \to 0 \) and so we have an indeterminate product that requires the use of l'Hospital's Rule: \[ \lim_{x \to -\infty} 7xe^x = \lim_{x \to -\infty} \frac{7x}{e^{-x}} = \lim_{x \to -\infty} \frac{7}{-7e^{-x}} = \lim_{x \to -\infty} -7e^x = 0. \] Thus the x-axis is a horizontal asymptote. **(E)** \( f'(x) = 7xe^x + 7e^x = ______ \) Since \( e^x \) is always positive, we see that \( f'(x) > 0 \) when \( x + 1 > 0 \), and \( f'(x) < 0 \) when \( x + 1 < 0 \). So \( f \) is increasing on \( (______, \infty) \) and decreasing on \( (-\infty, ______) \). **(F)** Because \( f'(-1) = 0 \) and \( f' \) changes from negative to positive at \( x = ______ \), \( f(-1) = -7e^{-1} \) is a local (and absolute) minimum. **(G)** \( f''(x) = (7 + 7x)e^x + 7e^x = ______ \) Since \( f''(x) > 0 \) if \( x > ______ \) and \( f''(x) < 0 \) if \( x < ______ \), \( f
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