9. Given f'(2) does not exist and f"(2) > 0, is x = 2 a maximum, minimum, or neither of f? Explain.

Calculus: Early Transcendentals
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question 9:**

Given \( f'(2) \) does not exist and \( f''(2) > 0 \), is \( x = 2 \) a maximum, minimum, or neither of \( f \)? Explain.

---

**Explanation:**

To determine if \( x = 2 \) is a maximum, minimum, or neither, we analyze the information provided about the derivatives of the function \( f \).

1. **First Derivative \( f'(2) \) does not exist:**
   - The non-existence of \( f'(2) \) suggests a potential cusp, vertical tangent, or discontinuity in the derivative at \( x = 2 \).

2. **Second Derivative \( f''(2) > 0 \):**
   - This indicates that the graph of \( f \) is concave up at \( x = 2 \).

Since the first derivative does not exist at \( x = 2 \), the typical test for critical points (where \( f'(x) = 0 \) or does not exist) cannot directly confirm if \( x = 2 \) is a local extremum. However, the concave up condition from the second derivative suggests a tendency for a local minimum.

Given this, \( x = 2 \) could potentially be a local minimum if the undefined derivative is due to a vertical tangent or cusp where the surrounding values of \( f \) suggest a dip. However, without further information about the graph or specific behavior of \( f \) around \( x = 2 \), it cannot be definitively classified as a minimum based solely on \( f''(2) > 0 \) when \( f'(2) \) does not exist. More information about the neighborhood of \( x = 2 \) is required for a conclusive determination.
Transcribed Image Text:**Question 9:** Given \( f'(2) \) does not exist and \( f''(2) > 0 \), is \( x = 2 \) a maximum, minimum, or neither of \( f \)? Explain. --- **Explanation:** To determine if \( x = 2 \) is a maximum, minimum, or neither, we analyze the information provided about the derivatives of the function \( f \). 1. **First Derivative \( f'(2) \) does not exist:** - The non-existence of \( f'(2) \) suggests a potential cusp, vertical tangent, or discontinuity in the derivative at \( x = 2 \). 2. **Second Derivative \( f''(2) > 0 \):** - This indicates that the graph of \( f \) is concave up at \( x = 2 \). Since the first derivative does not exist at \( x = 2 \), the typical test for critical points (where \( f'(x) = 0 \) or does not exist) cannot directly confirm if \( x = 2 \) is a local extremum. However, the concave up condition from the second derivative suggests a tendency for a local minimum. Given this, \( x = 2 \) could potentially be a local minimum if the undefined derivative is due to a vertical tangent or cusp where the surrounding values of \( f \) suggest a dip. However, without further information about the graph or specific behavior of \( f \) around \( x = 2 \), it cannot be definitively classified as a minimum based solely on \( f''(2) > 0 \) when \( f'(2) \) does not exist. More information about the neighborhood of \( x = 2 \) is required for a conclusive determination.
Expert Solution
Step 1 Let us find the given statement is maximum or minimum or neither

Given: x=2f'(2) = does not existf"2>0  

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