Sketch: f(x) = [x + 2]] − 1, on [−2,2]

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### Sketching the Function \( f(x) = \lfloor x + 2 \rfloor - 1 \) on the Interval \([-2, 2]\)

**Problem Statement:**

Sketch \( f(x) = \lfloor x + 2 \rfloor - 1 \) on the interval \([-2, 2]\).

**Function Breakdown:**

This function involves the floor function, denoted as \( \lfloor \cdot \rfloor \), which rounds down to the nearest integer. Specifically, \( f(x) \) can be described in two parts:

1. **Transformation of the Input:**
   The expression \( x + 2 \) adjusts the input \( x \) by adding 2. So, every value of \( x \) is increased by 2 before any other operations are applied.

2. **Applying the Floor Function:**
   The floor function, \( \lfloor x + 2 \rfloor \), takes the adjusted input and rounds it down to the nearest integer.

3. **Final Adjustment:**
   After the floor function has been applied, 1 is subtracted from the result.

**Interval Analysis:**

We consider the function on the range \([-2, 2]\). Here are the steps to generate the sketch:

- **For \( x \in [-2, -1) \):**
  \( x + 2 \) ranges from \( 0 \) to \( 1 \). So, \( \lfloor x + 2 \rfloor = \lfloor 0 \leq x + 2 < 1 \rfloor = 0 \).
  Therefore, \( f(x) = 0 - 1 = -1 \).

- **For \( x \in [-1, 0) \):**
  \( x + 2 \) ranges from \( 1 \) to \( 2 \). So, \( \lfloor 1 \leq x + 2 < 2 \rfloor = 1 \).
  Therefore, \( f(x) = 1 - 1 = 0 \).

- **For \( x \in [0, 1) \):**
  \( x + 2 \) ranges from \( 2 \) to \( 3 \). So, \( \lfloor 2 \leq x + 2 < 3 \rfloor
Transcribed Image Text:### Sketching the Function \( f(x) = \lfloor x + 2 \rfloor - 1 \) on the Interval \([-2, 2]\) **Problem Statement:** Sketch \( f(x) = \lfloor x + 2 \rfloor - 1 \) on the interval \([-2, 2]\). **Function Breakdown:** This function involves the floor function, denoted as \( \lfloor \cdot \rfloor \), which rounds down to the nearest integer. Specifically, \( f(x) \) can be described in two parts: 1. **Transformation of the Input:** The expression \( x + 2 \) adjusts the input \( x \) by adding 2. So, every value of \( x \) is increased by 2 before any other operations are applied. 2. **Applying the Floor Function:** The floor function, \( \lfloor x + 2 \rfloor \), takes the adjusted input and rounds it down to the nearest integer. 3. **Final Adjustment:** After the floor function has been applied, 1 is subtracted from the result. **Interval Analysis:** We consider the function on the range \([-2, 2]\). Here are the steps to generate the sketch: - **For \( x \in [-2, -1) \):** \( x + 2 \) ranges from \( 0 \) to \( 1 \). So, \( \lfloor x + 2 \rfloor = \lfloor 0 \leq x + 2 < 1 \rfloor = 0 \). Therefore, \( f(x) = 0 - 1 = -1 \). - **For \( x \in [-1, 0) \):** \( x + 2 \) ranges from \( 1 \) to \( 2 \). So, \( \lfloor 1 \leq x + 2 < 2 \rfloor = 1 \). Therefore, \( f(x) = 1 - 1 = 0 \). - **For \( x \in [0, 1) \):** \( x + 2 \) ranges from \( 2 \) to \( 3 \). So, \( \lfloor 2 \leq x + 2 < 3 \rfloor
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