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Basis: 1,000 kg of the product (i.e. the resulting mixed acid solution) Flow chart: x kg 44.4 wt% H2SO4 11.3 wt% HNO3 44.3 wt% water z kg 98 wt% H2SO4 O wt% HNO2 2 wt% water Product Mixing tank y ka O wt% H2SO. 90 wt% HNOa 10 wt% water 1.000 kg 60 wt% H2SO. 32 wt% HNO, 8 wt% water Unknowns: • Mass of Stream i (x) • Mass of Stream ii (y) • Mass of Stream iii (z ) Hence, we need 3 (three) equations Overall balance:

Basis: 1,000 kg of the product (i.e. the resulting mixed acid solution) Flow chart: x kg 44.4 wt% H2SO4 11.3 wt% HNO3 44.3 wt% water z kg 98 wt% H2SO4 O wt% HNO2 2 wt% water Product Mixing tank y ka O wt% H2SO. 90 wt% HNOa 10 wt% water 1.000 kg 60 wt% H2SO. 32 wt% HNO, 8 wt% water Unknowns: • Mass of Stream i (x) • Mass of Stream ii (y) • Mass of Stream iii (z ) Hence, we need 3 (three) equations Overall balance:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Basis: 1,000 kg of the product (i.e. the resulting mixed acid solution) Flow chart: x kg 44.4 wt% H2SO4 11.3 wt HNO2 44.3 wt% water z kg 98 wt% H2SO4 O wt% HNO2 2 wt% water Product 1,000 kg 60 wt9% H2SO. 32 wt% HNOa 8 wt% water Mixing tank y kg O wt% H2SO4 90 wt% HNO2 10 wt% water Unknowns: • Mass of Stream i (x) • Mass of Stream ii (y) • Mass of Stream iii (z ) Hence, we need 3 (three) equations Overall balance:
Transcribed Image Text:Basis: 1,000 kg of the product (i.e. the resulting mixed acid solution) Flow chart: x kg 44.4 wt% H2SO4 11.3 wt HNO2 44.3 wt% water z kg 98 wt% H2SO4 O wt% HNO2 2 wt% water Product 1,000 kg 60 wt9% H2SO. 32 wt% HNOa 8 wt% water Mixing tank y kg O wt% H2SO4 90 wt% HNO2 10 wt% water Unknowns: • Mass of Stream i (x) • Mass of Stream ii (y) • Mass of Stream iii (z ) Hence, we need 3 (three) equations Overall balance:
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