Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary tocalculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C.PropertyValueUnitsMelting point-94°CBoiling point65°CAHus3.18kJ/molΔHap37kJ/molG (s)48.7J/mol ·°C81.1J/mol °CGo (8)43.8J/mol ·°C Choose one or more:O A. q = n(81.1 J/mol -°C)AT, where ATis negativeO B. q= n(43.8 J/mol -°C)AT, where ATis positiveO C. q= n(81.1 J/mol °C)AT, where ATis positiveD. q = n(37 kJ/mol)O E. q= n(-37 kJ/mol)O F. q= n(3.18 kJ/mol)G. q = n(48.7 J/mol .°C)AT, where ATis negativeH. q = n(43.8 J/mol °C)AT, where ATis negativeO I. q= n(48.7 J/mol °C)AT, where ATis positiveO J. q= n(-3.18 kJ/mol)

Given : Mass of methanol = 5.0 Kg = 5000 g Initial temperature of methanol = -64 oC Final…

Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C. Property Value Units Melting point -94 °C Boiling point 65 °C AHtus 3.18 kJ/mol ΔΗap 37 kJ/mol Gp (s) 48.7 J/mol °C 81.1 J/mol °C 43.8 J/mol °C

Based on the thermodynamic properties provided for methanol (below), select from the following list the equation(s) necessary to calculate the amount of energy needed for 5.0 kg of methanol to go from -64°C to 88°C. Property Value Units Melting point -94 °C Boiling point 65 °C AHtus 3.18 kJ/mol ΔΗap 37 kJ/mol Gp (s) 48.7 J/mol °C 81.1 J/mol °C 43.8 J/mol °C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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