Based on the reactions: 1. 2H,Sg + 302 (g)→2SO2 (2) + 2H,0(2) AH1 = - 1035.94 kJ 2. 2SO3 (g) →2S02 (g) + 02 (g) A H2 = +197.78 kJ 3. 2H2Sg) + O2 (2) –→2S) + 2H¬O2) A H3 = +110.02 kJ Use Hess's law to calculate H for: A 2S(9) + 302 (g)→2SO3 (g) (s)

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Chapter1: Chemical Foundations
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3.
Based on the reactions:
1. 2H2S(g + 302 (2)→2SO2 (2) + 2H,0() AH1 = - 1035.94 kJ
%3D
2. 2503 (2) →2502 (g + 02 (2)
AH2 = +197.78 kJ
3. 2H2S(g) + 02 (g)→2S6) + 2H,O(g)
A H3 = +110.02 kJ
Use Hess's law to calculate H for:
2S(9) + 302 (g)→2SO3 (g)
Transcribed Image Text:3. Based on the reactions: 1. 2H2S(g + 302 (2)→2SO2 (2) + 2H,0() AH1 = - 1035.94 kJ %3D 2. 2503 (2) →2502 (g + 02 (2) AH2 = +197.78 kJ 3. 2H2S(g) + 02 (g)→2S6) + 2H,O(g) A H3 = +110.02 kJ Use Hess's law to calculate H for: 2S(9) + 302 (g)→2SO3 (g)
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